Question

A school lunch offers three different fruits and two different vegetables as side dishes. You are served two different side dishes at random. Find the probability that you are served a vegetable second given that you were served a fruit first.
The probability is ___%.

Answer 1

Answer: 50%

Step-by-step explanation:

probability of fruit first a is -> fruit and then veg or fruit and then fruit

= 3/5*2/5 +3/5*2/5

hence probability of a fruits first and then veg = (5/25)/(10/25)

=0.5

for percentage 0.5*100 = 50%