I think the answer is A
hope i helped
Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
x < -3
Step-by-step explanation:
Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.
−4x−3> 36/4
Divide 36 by 4 to get 9.
−4x−3>9
Add 3 to both sides.
−4x>9+3
Add 9 and 3 to get 12.
−4x>12
Divide both sides by −4. Since −4 is negative, the inequality direction is changed.
x< 12/-4
Divide 12 by −4 to get −3.
x < -3
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)
The above three expressions could be used to represent the numbers.
Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44
x = 11, y = 7, z = 44.