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2 years ago

Determine the moment m that will produce a maximum stress of 70 mpa on the cross-section

1 answer:

8 0

The moment M that will produce a maximum stress of 70 MPa on the cross-section of 177.3 will be 13.533 kN-m.

<h3>What is bending stress?</h3>

Bending stress is the typical stress that an item experiences when it is exposed to a heavy load at a specific spot, causing it to bent and fatigue.

The moment of inertia above the neutral axis will be

Iₓₓ = 99 x 84.7³/3 - (99 - 12 x 3) (84.7 - 12)³/3

Iₓₓ = 11983247 mm⁴

The moment of inertia below the neutral axis will be

Iₓₓ = 2 x 12 x (87 - 84.7)³/3 + 12 x 177.3³/3

Iₓₓ = 22294005 mm⁴

Then the moment of inertia about the neutral axis will be

Iₓₓ = + 11983247 + 22294005

Iₓₓ = 34277252 mm⁴

Then for maximum bending stress, we have

M = σ x Iₓₓ / y(max)

We have

σ = 70 MPa

Iₓₓ = 34277252 mm⁴

y(max) = 177.3

Then we have

M = 70 x 34277252 / 177.3

M = 13.533 kN-m

More about the bending stress link is given below.

brainly.com/question/24227487

#SPJ4

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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

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CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

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To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

<em>Substituting the required values: </em>

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

<em>Substituting the required values, </em>

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

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