well i cannot help u graph but u need to get them in y=mx+b form first
2x+y=4
y=-2x+4
2y-4x=6
2y=4x+6
y=2x+3
now that the problems are in y=mx+b form, u can graph them. the "b" is your y-intercept. you need to graph this first so what ever ur be is, put a point there on the y axis. then use your slope to plant your line. slope is rise/run. so for the top problem start at your y intercept and go down 2 and to the right 1. and for the bottem problem, start at your y intercept then go up 2 and to the right 1
HOPE THIS HELPED!
Answer:
Winston, Paul, Harry, Dillon
Step-by-step explanation:
btw are the numbers negative or is that just a dash beside the number? that is my only question lol
Because if they are negative it would be in this order that I put on top
Short Answer:Choice C [Third one down]
RemarkStart with the number so I can talk about the basic principle at work. The way to work it is to factor 162 into prime factors and hope there are at least 3 that are the same.
162 = 2 * 81
162 = 2 * 3 * 3 * 3 * 3
Now When you take the cube root of that, you get
![\sqrt[3]{2*2*2*2*3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2%2A2%2A2%2A2%2A3%7D%20)
Here's the rule for a cube root. For every 3 prime factors under the cuberoot sign, you take out one and throw the other two away. So for cube root of 81,
you would factor it as ∛(81) = ∛(3 * 3 * 3 * 3) = 3∛3.
So out of four 3s under the cube root sign, you have 1 outside the root sign and one inside the root sign. 2 of the four 3s have been thrown away.
Continuation.X firstYou want 2 xs outside the root sign
∛(x * x * x * x * x *x ) = (x * x) You have thrown away 2 xs for every x outside the cube root sign
C = 6 There are no left overs.
Y secondFor the ys, you need 1 outside and 2 inside the root sign. that's because you need 5 altogether.
∛(y * y * y * y * y) = y ∛y^2
Answer c = 6; d = 2
Choice C <<<<<< answer
Answer:
26
Step-by-step explanation:
you take all sides and add it up