<span>Answer: 100+25pi
The area of square part of arch is 10*10=100 the diameter of the circle is 10 therefor radius is 5 and area is \[\pi*r^2=\pi*25\] therefore total area is 100+25pi
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The real number would be 1.5 or 3/2 or 1 1/2
eighteen and eighty-nine thousanths
As it's a square root the underroot value must be greater than or equal to 0
So
let's find out the domain
- √4x+11≥0
- 4x+11≥0
- 4x≥-11
- x≥-11/4
Domain
