<span>b. Round to the nearest tenth. please mark brainly</span>
Answer:
40/3, 172/3, respectively
Step-by-step explanation:
x + 9 = 2y
2x = 2y + 2
x + 9 = 2(2x - 2)
4x - 4 = x + 9
3x - 13 = 0
x = 13/3
y = 40/6
RT = 13/3 + 9 = 40/3
QS = 160/3 + 4 = 172/3
Y = 2x +13
We know the slope to be 2 because lines that are parallel have the same slope. Then we can solve using slope-intercept form and the known point.
y = mx + b ----> Input known values
7 = (2)(-3) + b ---> Multiple
7 = -6 + b ----> Subtract 3 from both sides
13 = b
Now we can use the y-intercept found and the slope to write the equation above.
Answer:
5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2)
Step-by-step explanation:
In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:
x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)
x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)
Now that you have factored out the two quadratics, plug them into the equation.
5x - 3
(x+4)(x+2) (x+5)(x+2)
Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.
5x (x+5) - 3(x+4)
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:
5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
3:15 because its till 3 o'clock and in each 1 theres 5 inside so 3x 5 = 15.
Thats how I got the answer 3:15 o'clock.
Hoped it help! :D
