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oksian1 [2.3K]
3 years ago
9

Please solve this the question is in the picture

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

x : -3

Step-by-step explanation:

1) 15x-3(3x + 4) = 6 (distribute -3 to the numbers on the inside of parentheses)

2) 15x - 9x - 12 =6 (combine like terms 15x-9x = 6x)

3) -6x - 12 = 6 (add twelve to both sides, add the 12 to cancel out the 12)

4) -6x = 18 (divide the -6 on both sides)

5) x = -3

You might be interested in
could someone help me solve this equations with both comparison and elimination methods: 2(x+y)=120 and 2(2x+y/3)=170​
Gnom [1K]

Answer:

y=21 X=39

Step-by-step explanation:

expand brackets on first equation: 2x+2y=120

now divide the second equation by 2 on both sides:

2x+y/3=85

then subtract the second equation from the first equation

so (2x+2y) - (2x+y/3)

the 2x on both sides cancel out and you get 5/3 y

this is equal to the sum of the first equation subtract the second equation which is 35

divide both sides by 5/3 and you get

y=21

substitute y in the first equation and you get X=39

4 0
2 years ago
I need help asappppppppp
Arada [10]

Answer:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is a piecewise function, that represents the price in dollars  for the hours in an indoor park.

3 0
3 years ago
2. Using Vièta's theorem, find the solutions to the equation. a) x^2 - 3x + 2 = 0 b) x^2 + 2x - 15 = 0.
olga_2 [115]

Given:

\begin{gathered} x^2-3x+2=0 \\ x^2+2x-15=0 \end{gathered}

Required:

We need to find the solution by Vièta's theorem.

Explanation:

Compare 1st equation with

ax^2+bx+c=0

we get

\begin{gathered} a=1 \\ b=-3 \\ c=2 \end{gathered}

Vièta's theorem is

\begin{gathered} x_1+x_2=-\frac{b}{a} \\ x_1x_2=\frac{c}{a} \end{gathered}

\begin{gathered} x_1+x_2=3 \\ x_1x_2=2 \end{gathered}

now solve this equation and we get

\begin{gathered} x_1=1 \\ x_2=2 \end{gathered}

because addition of 1 and 2 is 3 and multiplication is 2

Now for 2nd equation

\begin{gathered} a=1 \\ b=2 \\ c=-15 \end{gathered}

apply Vièta's theorem

\begin{gathered} x_1+x_2=-2 \\ x_1x_2=-15 \end{gathered}

by this

\begin{gathered} x_1=3 \\ x_2=-5 \end{gathered}

because addition of 3 and -5 is -2 and multiplication is -15

8 0
1 year ago
Subtact: (3x + 4) - (x + 2)​
stiv31 [10]
Ok this is the answer to this question 2(x+1)
8 0
3 years ago
Read 2 more answers
You randomly select an integer from 0 to 19 ​(inclusively) and then randomly select an integer from 0 to 24 ​(inclusively). What
Mila [183]

Answer:

The probability of selecting 5 both​ times is 0.002.

Step-by-step explanation:

We are given that you randomly select an integer from 0 to 19 ​(inclusively) and then randomly select an integer from 0 to 24 ​(inclusively).

And we have to find the probability of selecting 5 both​ times.

As we know that the probability of an event is given by;

                Probability = \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

Now, here between integer from 0 to 19 ​(inclusively);

Number of times 5 comes = 1

Total number of integers = 20

Similarly, between integer from 0 to 24 ​(inclusively);

Number of times 5 comes = 1

Total number of integers = 25

So, the required probability = \frac{1}{20}\times \frac{1}{25}

                                              = \frac{1}{500} = 0.002

Hence, the probability of selecting 5 both​ times is 0.002.

5 0
4 years ago
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