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slavikrds [6]
3 years ago
9

I need the answer urgently please !!

Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Answer:

y = 2x

Step-by-step explanation:

Parallel line share the same slope, therefore we can put any parallel line of y = 2 (x + 1) in equation as: y = 2x + k

As the parallel has to intercept with point (2/3, 1/3), simply put the coordinate into the equation to get value of k

2/3 = 2(1/3) + k

k = 0

Therefore the equation of this parallel line is y = 2x

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What solid is generated when a rectangle is rotated about a line.? a)rectangular pyramid b)cylinder c) rectangular prism d) cone
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I believe it is a cylinder.
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Strike441 [17]

Answer:

x=±\sqrt{15/2}

Step-by-step explanation:

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Your team wins 18 medals at a competition. The metals are gold, silver, and bronze in a ratio of 2:4:3. How many of each metal d
Anarel [89]

Answer

Find out the how many of each metal did your team win.

To prove

As given

Your team wins 18 medals at a competition.

The metals are gold, silver, and bronze in a ratio of 2:4:3.

Let us assume that x be the scalar multiple of the gold, silver and bronze medal.

Thus

Number of gold medal = 2x

Number of silver medal = 4x

Number of bronze medal = 3x

Than the equation becomes

2x + 4x + 3x = 18

9x = 18

x = \frac{18}{9}

x = 2

Number of gold medal = 2 × 2

                                      = 4

Number of silver medal = 4 × 2

                                       = 8

Number of bronze medal = 3 × 2

                                           = 6

Therefore the number of gold medal are 4, silver medal are 8, bronze medal are 6.

3 0
4 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
I need help to figure out this question
ololo11 [35]

I think it would be 16.95 Hope this help you in someway.

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