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irakobra [83]
2 years ago
7

Get brainliest if you answer correctly! Make sure show your work!

Mathematics
1 answer:
Marrrta [24]2 years ago
6 0
<h3>Answer: 0.65</h3>

============================================================

Explanation:

Refer to the figure below.

Angle \text{A}\text{K}\text{B} is 72 degrees because we divide a full 360 degree rotation into five equal pieces. This divides in half to get angle \text{F}\text{K}\text{B} = 72/2 = 36 degrees.

Focus on triangle \text{F}\text{K}\text{B}

Use the tangent ratio to find that...

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(\text{K}) = \frac{\text{FB}}{\text{KF}}\\\\\tan(36) = \frac{2}{\text{KF}}\\\\0.726543 \approx \frac{2}{\text{KF}}\\\\ \text{KF}\approx \frac{2}{0.726543}\\\\ \text{KF}\approx 2.752762\\\\

--------------------

From that, determine the area of triangle BAK

\text{area} = \frac{\text{base}*\text{height}}{2}\\\\\text{area} = \frac{\text{AB}*\text{KF}}{2}\\\\\text{area} \approx \frac{4*2.752762}{2}\\\\\text{area} \approx 5.505524\\\\

There are five of these identical triangles to form the entire pentagon ABCDE. The triangles are a rotated copy of one another.

The area of pentagon ABCDE is 5*5.505524 = 27.52762 square units approximately.

--------------------

Now focus on right triangle LKF.

We'll use the cosine ratio to determine KL.

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(\text{K}) = \frac{\text{KL}}{\text{KF}}\\\\\cos(36) \approx \frac{\text{KL}}{2.752764}\\\\ \text{KL}\approx 2.752764\cos(36)\\\\ \text{KL}\approx 2.227033\\\\

Staying with the same triangle, we'll use the sine ratio this time to find the length of LF

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(\text{K}) = \frac{\text{LF}}{\text{KF}}\\\\\sin(36) \approx \frac{\text{LF}}{2.752764}\\\\ \text{LF}\approx 2.752764\sin(36)\\\\ \text{LF}\approx 1.618034\\\\

--------------------

Now find the area of triangle KGF

\text{area} = \frac{\text{base}*\text{height}}{2}\\\\\text{area} = \frac{\text{FG}*\text{KL}}{2}\\\\\text{area} = \frac{2*\text{LF}*\text{KL}}{2}\\\\\text{area} \approx \frac{2*1.618034*2.227033}{2}\\\\\text{area} \approx 3.603415\\\\

The area of the blue pentagon is roughly 5*3.603415 = 18.017075 square units.

--------------------

To summarize so far

  • area of pentagon ABCDE (red) = 27.52762 square units approximately
  • area of pentagon FGHIJ (blue) = 18.017075 square units approximately

We divide the two areas to get the ratio we want.

18.017075/27.52762 = 0.654509

Then this rounds to <u>0.65</u> when rounding to two decimal places.

The blue pentagon takes up roughly 65% of the area of the red pentagon.

In other words, if you threw a dart at random at the red figure, then you have around a 65% chance of landing inside the blue figure.

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