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3 years ago

State if the two triangles are congruent. If they are, state how you know.

Mathematics

1 answer:

Mars2501 [29]3 years ago

6 0

I believe that it is congruent by SAS

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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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3 years ago

Without graphing, determine whether the following pair of lines are parallel, perpendicular, or neither parallel nor perpendicul

Tomtit [17]

Write the equation of the lines in slope-intercept form (y=mx+b)

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$y=\frac{2}{5}x-4$

Second equation: solve y:

$\begin{gathered} 4x-10y=-7 \\ 4x-4x-10y=-4x-7 \\ -10y=-4x-7 \\ \frac{-10}{-10}y=\frac{-4}{-10}x-\frac{7}{-10} \\ \\ y=\frac{4}{10}x+\frac{7}{10} \\ \\ y=\frac{2}{5}x+\frac{7}{10} \end{gathered}$

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1 year ago

One solution to the problem below is 4.<br> What is the other solution?<br> y² - 16 = 0

ratelena [41]

Answer:

The 2 answers are 4 and -4

Step-by-step explanation:

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3 years ago

Drag each tile to the correct box. Not all tiles will be used. Consider function f. f(x)=7x-21 Place the steps for finding in th

dimulka [17.4K]

x=7x-21

Step-by-step explanation:

x=7x-21
21=7x-x
21=6x
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2 years ago

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3 years ago

Read 2 more answers