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Mumz [18]
3 years ago
6

Four cards numbered 1,5,8, and 9 are placed in a bag. A card is drawn at random and then replaced. The card is drawn at random a

gain. What is the probability that both cards drawn have the number 9?
A. 1/16
B. 1/9
C. 1/4
D. 1/2
WILL MARK BRAINLIEST
Mathematics
2 answers:
anzhelika [568]3 years ago
8 0

Answer: D

Step-by-step explanation:

so we know the probability of drawing a 9 is 25 percent  or 1/4 because 9 is only one and doesn't repeat.

So the cards we drawn cards we drawn 2 times so multiply 1/4 times two.

1/4 * 2/1= 2/4 = 1/2

Law Incorporation [45]3 years ago
3 0

Answer:

The answer is D. 1/2 I'm pretty sure. I'm usually pretty good at probability. Keep in mind this may be wrong.

Step-by-step explanation:

There is a 1/4 chance that ONE card drawn will have the number nine. That is only for one though. For 2 cards, it would be a 2/4 chance. Since it is not one of the answers, do the next best thing and simplify the probability. Divide 2/4 by 2 and it equals 1/2.

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Answer:

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How to Solve!-

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Pani-rosa [81]

Answer:

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Step-by-step explanation:

Ah, the sine law questions. Ok so you know \frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}. If you don't, voila. Obviously, the variables are different but we can use the same formula. So, we have

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3 years ago
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Step-by-step explanation:

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4 0
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Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec
expeople1 [14]

Answer:

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Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

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Step-by-step explanation:

For this case we have the following expression given:

cos x cot x + sin x

We know from math properties that the definition for cot is cot x = \frac{cos x}{sin x}

If we use this definition we got:

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\frac{cos^2 x}{sin x} +sin x

Now we can use the following identity:

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

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