Answer:
You should also try solving it yourself to make sure I did not make any mistake.
Step-by-step explanation:
Equation:
first we need the slope
So far the equation will look like this
Now to get b just pick one point and insert it into the equation. So I'll just pick (2,3)
when you solve this equation you'll get b
We could also check if we get the same answer if we instead use point (0,-1)
Now we have the equation!
Answer:
54
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The formula for finding the relationship between a secant and a tangent is
tangent length ^2 = external segment secant/full length of secant
In this case
60^2 = 48*(x + 48) Expand
3600 = 48*(x + 48) Remove the brackets/
3600 = 48x + 48^2 Expand
3600 = 48x + 2304 Subtract 2304 from both sides
3600 - 2304 = 48x
1296 = 48x Divide both sides by 48
1296 / 48 = x
x = 27
Compare your f(x)=1/2tan (2x+5) to
g(x)=a*tan (bx + c).
Note how b = 2.
The period of the given tangent function is pi/b, which here is pi/2, or 90 degrees. Multiplying x by 2 horizontallyl compresses the graph of tan x by a factor of 1/2.
Answer:
5.625 m/s²
Step-by-step explanation:
Intial velocity of car, u = 54 km/h = 54 × 5/18 m/s
u = 15 m/s
Car stops on applying brakes 20m
Displacement is covered by car ,S = 20m
finally car stops ∴ final velocity of car , v = 0
Now, use formula
V² = u² + 2aS , here a is Acceleration
⇒ 0 = (15)² + 2 × a × 20
⇒ -225 = 40a
⇒ a = -5.625 m/s² [ here negative sign shows that acceleration is opposite direction of motion of car ]
Hence, magnitude of acceleration = 5.625 m/s²