Question

Find the 9th term of the following geometric sequence: 1, –3, 9, –27. PLEASEEEEE HELP!!!!!!

Answer 1

Find common ratio
1 times -3=-3
-3 times -3=9

an=a1(r^(n-1))
a1=first term
r=common ratio
n=which term

an=1(-3)^(n-1)

9th term
n=9
an=1(-3)^(9-1)
an=1(-3)^(8)
an=1(6561)
an=6561


answer is D