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2 years ago

I need help, I have a test tomorrow and I didn't understand this exercise

Mathematics

1 answer:

just olya [345]2 years ago

7 0

Answer:

Step-by-step explanation:

Circumference = 2(pi)r

Radius = Circumference/2(pi)

Circumference = 37.68

Radius = 37.68/2(pi)

Radius = about 59.18760559

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Multiply 11w(w-22)=what?

ryzh [129]

11w(w-22) Multiply 11w times each term in the parenthesis
$11w(w-22)=11w^2-242w$

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3 years ago

What is 280.0575 as a fraction

LUCKY_DIMON [66]

Answer...

$280\frac{23}{400}$

Steps....

1) Rewrite the decimal number as a fraction with 1 in the denominator

2) Multiply to remove 4 decimal places. Here, you multiply top and bottom by $10^{4}$ = 10000

3) Find the Greatest Common Factor (GCF) of 2800575 and 10000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 25

4) Simplify the improper fraction!

8 0

2 years ago

Read 2 more answers

What is the approximate length of the diagonal of a square with side length of 20 centimeters

zhuklara [117]

Answer:28.28 cm

Explanation:

a² + b² = c²

20² + 20² = c²

c² = 400 + 400

c² = 800

c = √800

c = 28.28 cm

5 0

4 years ago

Read 2 more answers

Warren picked 3/4 of a pound of strawberries. That afternoon, Warren's

Crazy boy [7]

Answer: 2

Step-by-step explanation:

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4 years ago

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Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago