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3 years ago

What is the height of the platform?

Mathematics

2 answers:

mihalych1998 [28]3 years ago

8 0

40 metres.. Hope this helps u

jeyben [28]3 years ago

4 0

It's 40 ft.

Since the rocket is launched from a platform, then the height of the rocket at 0 seconds will be the height of the platform.
$h(t)=-16t^{2}+70t+40\\h(t)=-16(0)^{2}+70(0)+40\\h(t)=0+0+40=40ft$

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What is the following quotient? 5/√11-√3

kati45 [8]

ANSWER

$\frac{5( \sqrt{11} + \sqrt{3} )} {8}$

EXPLANATION

The given rational function is

$\frac{5}{ \sqrt{11} - \sqrt{3}}$

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

$\sqrt{11} - \sqrt{3}$

which is

$\sqrt{11} + \sqrt{3}$

When we rationalize we obtain:

$\frac{5( \sqrt{11} + \sqrt{3} )}{(\sqrt{11} - \sqrt{3} )( \sqrt{11} + \sqrt{3} )}$

The denominator is now a difference of two squares:

$(a - b)(a + b) = {a}^{2} - {b}^{2}$

We apply this property to get

$\frac{5( \sqrt{11} + \sqrt{3} )}{( \sqrt{11}) ^{2} - ( \sqrt{3}) ^{2} )}$

$\frac{5( \sqrt{11} + \sqrt{3} )}{11 - 3}$

This simplifies to

$\frac{5( \sqrt{11} + \sqrt{3} )} {8}$

$\frac{5 } {8}\sqrt{11} + \frac{5 } {8}\sqrt{3}$

8 0

3 years ago

Read 2 more answers

The area of a circular table cloth is 1,384.74 inches square. Using 3.14 for LaTeX: \pi

leonid [27]

Answer:

radius = 21

circumference = 138.88

Step-by-step explanation:

First divide the area by 3.14, this equal 441

441 is your radius squared.

Then you have to find the root of 441 which is 21.

radius = 21

diameter = twice the radius or 2 * radius

diameter = 21 * 2 = 42

diameter = 42

Then plug 42 in your circumference formula.

Which is then C = 3.14(42).

Which means the circumference is 131.88.

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2 years ago

The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c

timurjin [86]

Answer:

a) 28

Class Limits Class Boundaries Midpoint f Rf Cf

10 - 37 9.5-37.5 23.5 7 0.096 7

38 - 65 37.5-65.5 51.5 25 0.342 32

66 - 93 65.5-93.5 79.5 26 0.356 58

94 - 121 93.5-121.5 107.5 9 0.123 67

122 - 149 121.5-149.5 135.5 5 0.068 72

150 - 177 149.5-177.5 163.5 0 0.0 72

178 - 205 177.5-20.5 191.5 1 0.014 73

Total 73 1.0

The histogram is in attached file.

Step-by-step explanation:

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx

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3 years ago

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Answer:

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Step-by-step explanation:

get the x alone by subtracting 6787 from both sides

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Answer:

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Step-by-step explanation:

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