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2 years ago

What is the height of the platform?

Mathematics

2 answers:

mihalych1998 [28]2 years ago

8 0

40 metres.. Hope this helps u

jeyben [28]2 years ago

4 0

It's 40 ft.

Since the rocket is launched from a platform, then the height of the rocket at 0 seconds will be the height of the platform.
$h(t)=-16t^{2}+70t+40\\h(t)=-16(0)^{2}+70(0)+40\\h(t)=0+0+40=40ft$

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Compare the theoretical probability to the experimental probability of landing on H.

cestrela7 [59]

The correct statement comparing the theoretical and experimental probabilities is given as follows:

$\frac{1}{4} < \frac{7}{25}$ .

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

The theoretical probability is taken before any experiment. Since the four sections are equal, the theoretical probability is:

T(H) = 1/4.

The experimental probability is taken considering previous experiments. Out of 100 tosses, 28 landed on H, hence:

E(H) = 28/100 = 7/25.

Hence the correct statement is:

$\frac{1}{4} < \frac{7}{25}$ .

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

4 0

1 year ago

100 POINTS!! Express in radical form.

Vilka [71]

Answer:

27 4th root (x^3)

Step-by-step explanation:

(81x) ^ 3/4

We know (ab) ^c = a^c b^c

81 ^ (3/4) * x^3/4

We can rewrite 81 as 3^4

(3^4)^(3/4) * x^3/4

We know that a^b^c = a^ (b*c)

3^(4*3/4) * x^3/4

3^(3) * x^3/4

27 * x^3/4

27 4th root (x^3)

3 0

2 years ago

Read 2 more answers

Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided

DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

$H_0: \mu = 92$

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

$H_1: \mu > 92$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that $\mu = 92$

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that $n = 70, X = 93, \sigma = \sqrt{36} = 6$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}$

$z = 1.39$

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0

2 years ago

Based on the circle graph how many pounds of milk and eggs does the average American consume each year PLS EXPLAIN FOR BRAINLEST

Gnoma [55]

Answer:

H. 552

Step-by-step explanation:

Circle graph information:

Milk and eggs = x%
Fruits and vegetables = 38%
Cereals = 10%
Meat and fish = 10%
Sugar = 8%
Fats and oils = 4%

Total consumption = 1840 pounds per person

First, calculate the percentage of milk and eggs (the value of x).

Total percentages = 100%

⇒ x + 38 + 10 + 10 + 8 + 4 = 100

⇒ x + 70 = 100

⇒ x = 30

Therefore, 30% of food consumption is milk and eggs.

To calculate the number of pounds of milk and eggs the average American consumes each year, simply find 30% of the total consumption:

= 30% of 1840

= 30% × 1840

$=\sf \dfrac{30}{100} \times 1840$

= 552

Therefore, the average American consumes 552 pounds of milk and eggs each year.

5 0

1 year ago

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Complete the steps to solve for x 5/8x-1/3x=7

Blababa [14]

X=24 ........................

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2 years ago