<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =
factoring with leading coefficient:
for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
a=3, b=-2, c=-8
</span>a*c = 3*(-8) = -24
-24=(-6)*4 and -6+4=-2, so m=-6 and n=4
replace bx with mx + nx and factor by grouping
</span><span>
3x^2 - 2x - 8 = </span>3x^2 -6x + 4x -8 = 3x(x-2) + 4(x-2) = (3x+4)(x-2)
answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>
Answer:
Step-by-step explanation:
A right triangle must satisfy this equation: a^2 + b^2 = c^2
a= shortest length
b=medium length
c=the longest length
a triangle with sides 4,5,6 will satisfy not this equation because:
4^2 + 5^2 ≠ 6^2
16+25 = 41
41 ≠ 36
so the answer is C.
Hope this helps.
-Jabba
The two given angles are vertical angles which mean they are the same:
9x + 72 = 4x + 112
Subtract 72 from bot sides:
9x = 4x + 40
Subtract 4x from both sides:
5x = 40
Divide both sides by 5:
X = 8
The slope is 3/1. (Rise over run, rise 3 run 1)