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Oksi-84 [34.3K]
3 years ago
8

(14x-5)-(-3x+2)A. 11x-3B. 17x-7C. 17x-3D. 11x-7

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0
The answer would be B) 17x-7
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Becca has a biscuit recipe that uses 2/3 of a tablespoon of salt for every 3/4 of a cup of flour. In order to have enough biscui
MAXImum [283]
 2/3   -  3/4
   x    -  3

x= (2/3 * 3) / (3/4) = 2 * (4/3) = 8/3 = 2 and 2/3 of tablespoon of salt  
3 0
3 years ago
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Put the following equation of a line into slope-intercept form, simplifying all fractions. 4x – 24y = 72​
kaheart [24]
4x - 24y = 72

First subtract 4x from each side

-24y = -4x + 72

Divide each side by -24 so y is by itself

y = -4/-24x + 72/-24

To simplify -4/-24, the greatest common factor they have is -4, so divide the numerator and denominator by -4

y = 1/6x + 72/-24

To simplify 72/-24, the greatest common factor is 24, so divide the numerator and denominator by 24

y = 1/6x - 3

This is now in slope intercept form
6 0
3 years ago
Which gives 28 + 24 as a product of the GCF and a sum?
yanalaym [24]

Answer:

I believe it is A

Step-by-step explanation:

Let me know if it is wrong

3 0
3 years ago
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
charle [14.2K]

Answer: t = - 5 ∈ I_{1} = ( -∞ , -4 )

Step-by-step explanation:

The standard form of O.D.E is written as :

y^{1} + p(t) = g(t)

Equation given :

(16-t^{2} )y^{1} + 9ty = 5t^{2} ,       y(-5) = 1

The first thing to do is to write the O.D.E in standard form , that is we will divide through by 16 - t^{2} , so we have

y^{1} + \frac{9ty}{16-t^{2}}=\frac{5t^{2}}{16-t^{2}}

With this , we can see that p(t) and g(t) are both continuous in the same domain. Therefore , the intervals are :

I_{1} = ( -∞ , -4 )

I_{2} = ( - 4 , 4 )

I_{3} = ( 4 , -∞ )

recall that y(−5) = 1 , then t = -5

This means that :

t = - 5 ∈ I_{1} = ( -∞ , -4 )

3 0
4 years ago
Find all solutions for a triangle with a=14 b=12 B=90
blagie [28]

we know that

if angle B is equal to 90 degrees

so

we have a right triangle

but

the opposite side to the right angle is the hypotenuse

and

the hypotenuse is the long side of the triangle


in this problem, the hypotenuse is b=12

and

12 is not greater than 14

therefore


with these dimensions you can not form a triangle

there is no solution


5 0
4 years ago
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