The answer would be A)$679.80
The reason for this is let’s start with the mark up of 10%. Meaning we will add the result of the markup to our first number We would take 1000*.1 which would give us 100.
Add that to the original to give you $1,100.
Then the item was discounted for 40% meaning we take away the result of 1,100*.4 which equals 440. 1100-440=660.
Then taxes are added on to the total so you would do 660*.03 which would give you 19.8
660+19.8 gives you$679.80.
Which quadratic equation fits the data in the table? x -5,-2,-1,0,3,4,6 y 33,9,5,3,9,15,33
mojhsa [17]
Answer:
y = x² − x + 3
Step-by-step explanation:
Quadratic equation is:
y = ax² + bx + c
Pick three points and plug in. I'll choose (-2, 9), (-1, 5), and (0, 3).
9 = a(-2)² + b(-2) + c
5 = a(-1)² + b(-1) + c
3 = a(0)² + b(0) + c
9 = 4a − 2b + c
5 = a − b + c
3 = c
We know c = 3, so substitute into the first two equations:
9 = 4a − 2b + 3
5 = a − b + 3
0 = 4a − 2b − 6
0 = a − b − 2
Solve by elimination or substitution.
b = a − 2
0 = 4a − 2(a − 2) − 6
0 = 4a − 2a + 4 − 6
0 = 2a − 2
a = 1
b = -1
Therefore:
y = x² − x + 3
So if y=-5x-23 then we can plug that value in for y in x-10y=6, so it becomes
x-10(-5x-23)=6
x+50x+230=6
51x=-224
x=-4.39
plug this x value into the equation y=-5x-23
y=-5(-4.39)-23
y=21.95-23
y=-1.05
Exact form: -1/10
decimal form: -0.1
Answer:
Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
Step-by-step explanation:
Considering the graph
Given the vertices of the segment AB
Finding the length of AB using the formula
units
Given the vertices of the segment JK
From the graph, it is clear that the length of JK = 5 units
so
units
Given the vertices of the segment GH
Finding the length of GH using the formula
![\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%5C%3A%7D%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)
units
Thus, from the calculations, it is clear that:
Thus,
Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
