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Nesterboy [21]
3 years ago
15

Solve the inequality 16

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

I thought I knew how to do this but ig I forgot ill be back in a little with the anwser.

Step-by-step explanation:

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Evaluate the function f(x)=x^2-5x+ 5 at the given values of the independent variable and simplify
11111nata11111 [884]

Step-by-step explanation:

The given function is :

f(x)=x^2-5x+ 5

(a) To find f(9), put x = 9 in the above expression.

f(9)=9^2-5(9)+ 5=41

(b) To find f(x+7), put x = x+7 in the above expression.

f(x+7)=(x+7)^2-5(x+7)+ 5\\\\=x^2+14x+49-5x-35+5\\\\=x^2+9x+19

(c) To find f(-x), put x = -x in the above expression.

f(-x)=(-x)^2-5(-x)+ 5\\\\=x^2+5x+5

Hence, this is the required solution.

8 0
3 years ago
What is the LCD of x-3, x+3, and <img src="https://tex.z-dn.net/?f=x%5E2-9" id="TexFormula1" title="x^2-9" alt="x^2-9" align="ab
Agata [3.3K]
The least common denominator is one, since all of these numbers are actually whole numbers. They're actually all \frac{x-3}{1} \frac{x+3}{1} \frac{x^2-9}{1}
If you mean the greatest common factor, then it's obviously x
3 0
3 years ago
Which is the domain of the function f(x) = -5/6(3/5)x ?
gtnhenbr [62]
A because i did this 1 month ago

k12
4 0
3 years ago
Divide the 4th degree polynomial
iragen [17]

Answer:

  • quotient: 10x +16
  • remainder: 28x^2 +10x +22

Step-by-step explanation:

The attachment shows the steps.

  quotient: 10x +16

  remainder: 28x^2 +10x +22

_____

Polynomial long division is easier than numerical long division because you only need to examine the first terms to determine the quotient term.

The first quotient term is 10x^4/x^3 = 10x.

The second quotient term is 16x^3/x^3 = 16.

When the leading dividend term is lower degree than the divisor, that dividend is the remainder.

4 0
3 years ago
Round your answer to the nearest tenth
xxTIMURxx [149]

Answer:

19.0

Step-by-step explanation:

<em>1</em><em>9</em><em>.</em><em>0</em><em> </em><em>is </em><em>the</em><em> correct</em><em> answer</em><em>.</em>

8 0
3 years ago
Read 2 more answers
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