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2 years ago

3. What challenges do you anticipate in implementing some of the above steps? Explain.

1 answer:

6 0

In implementing some of your steps, anticipate the challenges as they are bound to e related to your specific goal.

<h3>What are challenges?</h3>

Generally, challenges are simply a competitive situation to determine who is superior in a specific field.

In conclusion, in carrying out set goals, missions, or said steps or series of activities we tend to meet challenges, and these challenges are anticipated by the nature of activity.

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Prompt<br> What is the difference between liquid and illiquid assets?

Lynna [10]

Answer:

Liquid assets may be cash or property that can readily be converted to cash without a substantial loss in value. While on the other hand, Illiquid or fixed assets are possessions of value that are held long-term such as a home, land or equipment.

Hope this helps

4 0

3 years ago

Read 2 more answers

A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius

anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

$T^2 \alpha a^3$

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 $\times 10^8 \ km$

Therefore, $T^2 = ca^3$

$c= \dfrac{365^2}{(1.496 \times 10^8)^3}$

c = 3.9791 $\times 10^{20} \ day^2/km^3$

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

$T^2 = ca^3$

$a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}$

$a^3 = 2.9092 \times 10^{27}$

$a= \sqrt[3]{2.9092 \times 10^{27}}$

a = 1.4275 $\times 10^9 \ km$

However, the velocity for a perihelion = 10.18 km/s

Using the formula

$v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})}$ to calculate the radius, we have:

G = $6.674 \times 10^{-11}$

M = $1.989\times 10^{30} \ kg$

r = perihelion

$v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})$

$(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30} ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})$

$7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}$

$\dfrac{2}{r} = 1.4824 \times 10^{-12}$

$r = \dfrac{2}{1.4824 \times 10^{-12}}$

$r = 1.349 \times 10^{12}$

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

$1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)$

$1.349 \times 10^{12} - 1.425 \times 10^{12}= - 1.425 \times 10^{12} (e)$

$-7.6\times 10^{10}= - 1.425 \times 10^{12} (e)$

$\dfrac{-7.6\times 10^{10}}{- 1.425 \times 10^{12}}= (e)$

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

$r = 1.425 \times 10^{12} ( 1 + 0.0533)$

$r = 1.50 \times 10^{12} \ m$

to nautical miles, we have:

$r = 1.50 \times 10^{12} \times 0.00054 \ nautical \ mile$

radius of aphelion $\mathbf{r = 8.10 \times 10^8}$ nautical miles

In respect to the value of a( i.e $1.4275 \times 10^9 \ km)$

the body of the solar system is Saturn

5 0

3 years ago

Tuity Fruity Beverage Company's operating activities for the year are listed below. Purchases $140 comma 700 Operating expense

blsea [12.9K]

Answer:

The cost of goods sold for the year is $134,300

Explanation:

The cost of goods sold for the year = Beginning inventory + Merchandise Purchased - Ending inventory

Tuity Fruity Beverage Company's purchases $140 comma 700 and has beginning inventory 12 comma 600, ending inventory 19 comma 000.

Therefore:

The cost of goods sold for the year = $12,600 + $140,700 - $19,000 = $134,300

3 0

3 years ago

The rule of supply and demand says that

LuckyWell [14K]

Answer:

C ) As demand increases,price increases

4 0

3 years ago

Read 2 more answers

Jeff got a part-time job delivering groceries for $15/hour and grossed $8,200

solniwko [45]

Answer:

Income = $8,200

Less:

Federal tax 10% = -$820

State tax at 5.5% = -$451

FICA at 7.65% = -$627.30

Total deduction = -$1,898.30

Net pay = $6,301.70

4 0

3 years ago