Find the center of the circle whose equation is (x - 5) 2 + (y + 3) 2 = 6.

Mathematics

1 answer:

Komok [63]2 years ago

4 0

Answer:

(5, -3)

Step-by-step explanation:

Solve for x and solve for y by making each set of brackets equal to 0

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Solve the equation by completing the square. x^2-7x-4=0. Have to show steps.

Paul [167]

X^2-7x-4=0
(x-7/2)^2-(7/2)^2-4=0
(x-7/2)^2-(7)^2/(2)^2-4=0
(x-7/2)^2-49/4-4=0
(x-7/2)^2+(-49-4*4)/4=0
(x-7/2)^2+(-49-16)/4=0
(x-7/2)^2+(-65)/4=0
(x-7/2)^2-65/4=0
(x-7/2)^2-65/4+65/4=0+65/4
(x-7/2)^2=65/4
sqrt[ (x-7/2)^2 ]=+-sqrt(65/4)
x-7/2=+-sqrt(65)/sqrt(4)
x-7/2=+-sqrt(65)/2
x-7/2+7/2=+-sqrt(65)/2+7/2
x=7/2+-sqrt(65)/2
x=[7+-sqrt(65)]/2
x1=[7-sqrt(65)]/2
x2=[7+sqrt(65)]/2

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A city has 4 new houses for every 9 old houses. If there are 28 new houses in the city, how many old houses are there?

Ratling [72]

The answer is B because 4 X 7 is 28 so 9 times 7 is 63

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Tatiana [17]

Answer:

$\frac{p^{4} x^{24}+6p^{2}q^{2}x^{12}+q^{4}+4p^{3}qx^{18}+4pq^{3}x^{6}}{x^{12} }$

Step-by-step explanation:

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KatRina [158]

A quick way to do this is by recalling the fact that $-1\le\cos x\le1$ , so the largest value that $\cos ax$ alone (for any real value of $a$ ) can take on is 1.

This means $-3\le3\cos2x\le3$ , and so $1\le3\cos2x+4\le7$ .

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I need help ASAP please

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1

a= 6/12 or one half.
b= 1/2 , one half.

step by step:

multiply the top numbers by eachothers
do the same with the bottom.

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