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rosijanka [135]
2 years ago
12

Here’s question two pls help

Mathematics
2 answers:
atroni [7]2 years ago
6 0

Answer:

Total is 24

HALF THE TOTAL- 12

Impossible event- Picking a black marble

Certainty- Picking either one of a green, red, or blue marble

As likely as not event would be picking a blue marble(probability of that is 12/24= 1/2)

More likely than not event would be picking either a red or blue marble whose probability in total is 18/24= 3/4.

Unlikely event- You not picking anything at all

Step-by-step explanation:

Hi. Took me some time to attempt all problems, but the key to solving these problems is to ahve a firm foundation of basic probability. Things like likeliness and unlikelieness are all outskirts of probability, so I would reccomend getting yourself familiar with those basics. You GOT THIS!

weeeeeb [17]2 years ago
4 0

Answer:

Lake A

Step-by-step explanation:

FIrst off I am not sure how this connects with the lake but based on what I have seen and learned so far I would say that the Answer to #3 on the last question is Lake A and for the second part based on the data set I am unsure of how to do that but at least u got the answer to #3? sorry if this is no help.

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*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
Which of the following is a result of shifting a circle with equation
ladessa [460]
The answer might be B, but realize if a circle is shifting both y and x can’t decrease.. and both cant increase at the same time.
3 0
3 years ago
If a right triangle has a hypotenuse of 13 inches and a leg of 5 inches, how could you use the Pythagorean Theorem to find the m
zaharov [31]
12,5,13 are Pythagorean triplets..

so, missing side will be 12 inches

hope it helps


Hyp^2 = Base^2 + perpendicular^2
4 0
3 years ago
Read 2 more answers
Can anyone help me please ? Hurry
jeka94

Answer:

1) x=z-m

3) x=g-c

5) a=u-k

7) x=u+k

9) x=k-w+v

11) x=d+r-c

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Step-by-step explanation:

6 0
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A fellow classmate tosses 5 coins and finds that 3 of them come up tails. Which of the following is the best conclusion for her
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