Probability of randomly rolling a 3 is 1/4
Step-by-step explanation:
Step 1:
It is given that a tetrahedron has 4 sides with 1,2,3 and 4 and is randomly rolled. We need to compute the probability of randomly rolling a 3.
Step 2:
Probability of an event = (Favorable outcomes) / (Total outcomes).
There are 4 total outcomes when the tetrahedron is rolled, these are the values 1 to 4.
The only favorable outcome is getting a 3
Probability of getting a 3 when the tetrahedron is randomly rolled = 1/4
Step 3:
Answer:
Probability of randomly rolling a 3 is 1/4
2/7 because its a part to whole ratio.
9514 1404 393
Answer:
- 69
- 100
- -24
- 1/729
Step-by-step explanation:
Put the numbers where the variables are and do the arithmetic. Your calculator can help.
1. 6x -2y +5y = 6(10) -2(3) +5(3) = 60 -6 +15 = 69
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2. add 16 to find x.
x -16 = 29
x = 45
Then do the substitution:
2(45 +5) = 2(50) = 100
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3. 3(4²) -4(18) = 3(16) -4(18) = 48 -72 = -24
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4. (1/9)³ = (1/9)(1/9)(1/9) = 1/(9·9·9) = 1/729
Let x be the weight of the candy in pounds, then 0.9x is the weight of the milk chocolate in pounds
The weight of the caramels in the candy is 3 pounds, so
An equation that can be used find the total number of pounds of milk chocolate and caramels in the candy is
0.9x + 3 = x ⇒ x = 30
So there are 0.9(30) = 27 pounds of milk chocolate in the candy.
hope this helps
The solution set of the inequality as given in the task content is; x ≥-10.
<h3>What is the solution set of the inequality?</h3>
It follows from the task content that the given inequality is; 5x+13≥−37.
On this note, the inequality can be solved as follows;
5x+13≥−37
5x ≥−37 -13
5x ≥−50
x ≥-10.
Read more on inequalities;
brainly.com/question/24372553
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