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r-ruslan [8.4K]
3 years ago
9

The National Safety Council publishes information about automobile accidents in Accident Facts. According to that document, the

probability is .40 that a traffic fatality involves an intoxication or alcohol-impaired driver or nonoccupant. In eight traffic fatalities, find the probability that the number which involve an intoxicated or alcohol-impaired driver or nonoccupant is
Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

P(X = x) = C_{8,x}.(0.4)^{x}.(0.6)^{8-x}

In which x is the number of which we want to find the probability.

Step-by-step explanation:

For each traffic fatality, there are only two possible outcomes. EIther it involved an intoxicated or alcohol-impaired driver or nonoccupant, or it didn't. Traffic fatalities are independent of other traffic fatalities, which means that the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability is .40 that a traffic fatality involves an intoxication or alcohol-impaired driver or nonoccupant.

This means that p = 0.4

Eight traffic fatalities

This means that n = 8

Find the probability that the number which involve an intoxicated or alcohol-impaired driver or nonoccupant is

This is P(X = x), in which x is the number of which we want to find the probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = x) = C_{8,x}.(0.4)^{x}.(0.6)^{8-x}

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I need the mean, medium, and the mode for these numbers [4,10,11,15,16,16,18,19]​
iren [92.7K]

Hello here would be your answers:

mean: 13.6  

mediun: 15.5  

mode: 16

remember it like this

Mean is the average

Mode is the most often number

Range is when you subtract the smallest number from the largest number

Medium is the middle number when you line it up from the greatest to the least.

hope this helps!

7 0
2 years ago
What is the least common multiple of 28 and 8
nordsb [41]
LEAST COMMON MULTIPLE is 56

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6 0
3 years ago
Read 2 more answers
A building makes a 90° angle with the ground. A ladder leans against the building, making a 110° exterior angle with the ground.
liberstina [14]

<u>Answer:</u>

A building makes a 90^{\circ} angle with the ground .The two interior angles are 70^{\circ} and 20^{\circ}

<u>Solution: </u>

Given, a ladder which is against the building wall makes an exterior angle of 110^{\circ}

And building makes a  90^{\circ} angle with the ground.

So, altogether it makes a right angle triangle with ladder as hypotenuse and ground as base leg and building as another leg.  

Now, we know that, sum of exterior angles and interior angles equals to 180^{\circ}

Here, in the case of ground and ladder, exterior angle is 110^{\circ} and interior angle is unknown.

Exterior angle + interior angle = 180

110 + interior angle = 180

Interior angle = 180 – 110

Interior angle = 70^{\circ}

We have found one of the two interior angles of right angle triangle.

We know that, sum of angles in a triangle is 180 degree

Known Interior angle + unknown interior angle + right angle = 180

70 + unknown interior angle + 90 = 180

Unknown interior angle + 160 = 180

Unknown interior angle = 180 - 160

Unknown interior angle = 20^{\circ}

Hence the two interior angles are  70^{\circ} and 20^{\circ}

7 0
3 years ago
Find the number of ways to distribute six different toys to three different children such that each child gets at least one toy.
Lisa [10]

Answer:

Step-by-step explanation:

Given that there are six different toys and they are to be distributed to three different children.

The restraint here is each child gets atleast one toy.

Let us consider the situation as this.

Since each child has to get atleast one toy no of ways to distribute

any 3 toys to the three children each.  This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways

So 3 toys to each one in 6x5x4 =120 ways

Now remaining 3 toys can be given to any child.

Hence remaining 3 toys can be distributed in 3x3x3 =27 ways

Total no of ways

= 120(27)

= 3240

8 0
2 years ago
The principal of East High School wants to buy a new cover for the sand pit used in the long-jump competition. He measured the s
Ganezh [65]

Answer: area is 286.16 ft²

Step-by-step explanation:

Length of the sand pit is 29.2 feet and the width is 9.8 feet.

L= 29.2 ft

W = 9.8 ft

To find out the area, all we have to do is multiply the lenght by the width:

And do not forget that to calculate the area, all units must be the same and for the area, it is always the unit squared, in this case, feet square or simply (ft²).

A = l*w

A = 29.2 * 9.8 = 286.16 ft²

3 0
3 years ago
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