<span>Let the number of hours she works be x
2x+15 15 more than twice the
3x-15 15 less than 3 times the hours she worked
2x+15=3x-15
3x-2x= 30
x= 30
the number of hours she worked is 30
</span>
Answer:
g(f(2)) = 11
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x - 2
g(x) = x² - 5
<u>Step 2: Find g(f(2))</u>
f(2)
- Substitute in <em>x</em>: f(2) = 3(2) - 2
- Multiply: f(2) = 6 - 2
- Subtract: f(2) = 4
g(f(2))
- Substitute in <em>x</em>: g(4) = 4² - 5
- Exponents: g(4) = 16 - 5
- Subtract: g(4) = 11
Hi there!
So to get this we just need to multiply 300 by 5 because it is 1/5 of the hour work. 300 x 5 = 1500 light bulbs. Hope this helps!
2x - 7y = 14
x intercept is when y=0
2x = 14
x = 14/2 = 7
Answer: x intercept is 7
y intercept is when x=0
-7y = 14
y = -2
Answer: y intercept is -2
