Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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Answer:
A. -1⅕
Step-by-step explanation:
I am joyous to assist you anytime.
Answer:
uh what about bang thats four words id.k
Step-by-step explanation:
Y=0.5x-0.5
( u find the slope using rise/run then after finding the slope u use the equation and a point on the graph to find the y-intercept
Answer:
<h2>Net proceed= s-0.98nd-11</h2>
Step-by-step explanation:
Given that the shares cost $d
n shares will be =$dn
paid 2% commission to her broker= (2/100)*nd= 0.02nd
sold the share for $s
paid a fee of $11
Her net proceeds algebraically will be
Net proceed= s-nd-11-0.02nd
collect like terms
Net proceed= s-(nd-0.02nd)-11
Net proceed= s-0.98nd-11
