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Scorpion4ik [409]
3 years ago
11

Find the Mean Absolute Deviation. 12 5 7 8 15 15 2 8

Mathematics
1 answer:
patriot [66]3 years ago
8 0
The mean would be 7 I think I am not sure
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You buy Apple stock for $120 per share over a period of time the stock value increased at a weekly rate of 5% you sell the stock
Rainbow [258]

Answer:

8.31  weeks

Step-by-step explanation:

Given that the cost of one share of Apple stock, C=$120

Rate is the increment of the stock value, R= 5%/week=0.05 / week.

Assuming that after t week, the stock has been sold for $180.

Since the stock value increased at 5% every week, so, the interest is compounded weekly, so

S=C\left(1+R\right)^t \\\\ \Rightarrow 180 = 120\left(1+0.05\right)^t \\\\  \Rightarrow 180 = 120\left(1.05 )^t \\\\

\Rightarrow \frac{180}{120}=1.05^t \\\\\Rightarrow 1.5=1.05^t

\Rightarrow \ln(1.5)=t \ln(1.05) [taking log both sides]

\Rightarrow t=\frac {\ln(1.5)}{\ln(1.05)}=8.31 weeks

Hence, after 8.31  weeks the stock has been sold for $180.

6 0
3 years ago
MARKING BRAINLIEST!!!!<br> find each product -7/9 x 3/5<br><br> -27/45<br> -7/15<br> 7/15<br> 27/45
Leno4ka [110]

Answer:

1.  .466-

2.  -0.6

3.  .466-

4.   .466-

5.  0.6

Step-by-step explanation:

3 0
3 years ago
Please everything that I put on this app no one has answered I’m just wasting points now
zloy xaker [14]

Answer:

QR=18

Step-by-step explanation:

QR/QO =QS/QP (proportionality theorem...OP||RS )

QR/39 =24/52

52QR = 24(39)

52Q2=936

QR=18

3 0
3 years ago
P2q2+pq–q3–p3 =<br><br> for p=0.5 and q = −0.5<br><br><br> Please help!!!
Aleksandr [31]
In order to answer the question, we simply substitute the value of p and q to the given expression and solve. We do as follows:

<span>P^2q^2+pq–q^3–p^3 
</span>0.5^2(-0.5)^2+0.5(-0.5)–(-0.5)^3–(0.5)^3
-3/16 or -0.1875

Hope this answers the question. Have a nice day. 
5 0
3 years ago
X to the third plus x minus 7 equals -3 square root of x - 1
Ugo [173]

Answer:

  x ≈ 1.5004

Step-by-step explanation:

We suppose your equation is ...

  x^3+x-7=-3\sqrt{x-1}

Squaring both sides and subtracting the right side gives ...

  x^6 +2x^4 -14x^3 +x^2 -23x +58 = 0

This 6th-degree equation has two positive real roots, near x=1.5, and x=2. The root at x=2 is extraneous. The one near x=1.5 is irrational.

5 0
3 years ago
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