Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
Answer:
![(0, \frac{3}{10})](https://tex.z-dn.net/?f=%280%2C%20%5Cfrac%7B3%7D%7B10%7D%29)
Step-by-step explanation:
To find the y-intercept of a graph, we can simply set the value of 'x' equal to 0. If we substitute this into the equation y= x²+3/10, we get:
y= 0²+3/10
y=3/10.
Answer:
![P(n)=300n-2500](https://tex.z-dn.net/?f=P%28n%29%3D300n-2500)
Step-by-step explanation:
The fixed cost to operate the boathouse is $2500/month. It also has a cost of $600/month for every boat it docks.
If n boats are docked, then the total monthly cost is expressed as
![C=2500+600n](https://tex.z-dn.net/?f=C%3D2500%2B600n)
The boathouse charges $900/month for every boat docked. The revenue for n boats will be
![R=900n](https://tex.z-dn.net/?f=R%3D900n)
The profit function can be constructed by subtracting revenue and cost
![P(n)=900n-(2500+600n)=300n-2500](https://tex.z-dn.net/?f=P%28n%29%3D900n-%282500%2B600n%29%3D300n-2500)
The width would be 4.666666666666666666666, then the sixes just keep continuing on and on
Answer:
the answer is A
Step-by-step explanation:
the Pythagorean theorem is a squared + b squared = c squared (c always being the hypotenuse and a and b being the legs. 2 (4) squared pus 10 (100) squared=104 then you would use the square root of 104. 104 does not have a whole number square so the answer is ![\sqrt{104\\](https://tex.z-dn.net/?f=%5Csqrt%7B104%5C%5C)