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adoni [48]
2 years ago
15

Find the values of x and y. 2(5x- 5)° (5y + 5)º (7y - 9° (6x + 50)

Mathematics
1 answer:
Amanda [17]2 years ago
4 0

The values of x and y are 15 and 7 respectively

The angles formed from the intersection of two lines at X are equal and vertically opposite angles.

From the figure shown, we can conclude that:

2(5x-5) = 6x + 50 (vertically opposite angle)

Expand

10x - 10 = 6x + 50

10x - 6x = 50 + 10

4x = 60

x = 60/4

x =15

Similarly;

5y + 5 = 7y - 9

Collect the like terms;

5y - 7y = -9 - 5

-2y = -14

y = 14/2

y = 7

Hence the values of x and y are 15 and 7 respectively

Learn more here: brainly.com/question/15198257

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3 years ago
How many solutions does the equation −2a + 2a + 7 = 8 have? One Two None Infinitely many
aleksandrvk [35]

Answer:

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5 0
3 years ago
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The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
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Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
What's y=-4+15 in standard form
kotykmax [81]

Answer:

y=1.1×10¹

Step-by-step explanation:

y=-4+15

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5 0
2 years ago
Is 2/4 greater than or less than 1/2?
Paladinen [302]

Answer:

2/4 is equal to 1/2

Step-by-step explanation:

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