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2 years ago

Find the values of x and y. 2(5x- 5)° (5y + 5)º (7y - 9° (6x + 50)

Mathematics

1 answer:

Amanda [17]2 years ago

4 0

The values of x and y are 15 and 7 respectively

The angles formed from the intersection of two lines at X are equal and vertically opposite angles.

From the figure shown, we can conclude that:

2(5x-5) = 6x + 50 (vertically opposite angle)

Expand

10x - 10 = 6x + 50

10x - 6x = 50 + 10

4x = 60

x = 60/4

x =15

Similarly;

5y + 5 = 7y - 9

Collect the like terms;

5y - 7y = -9 - 5

-2y = -14

y = 14/2

y = 7

Hence the values of x and y are 15 and 7 respectively

Learn more here: brainly.com/question/15198257

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Step-by-step explanation:

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2 years ago

A triangle has a base length given by the equation b = 2x + 4 and a height given by the equation h

Anna11 [10]

It’s 230 I hope this helps

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3 years ago

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$

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Crazy boy [7]

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