When hav epoins (x1,y1) and (x2,y2)
slope is (y2-y1)/(x2-x1)
(-3,4) and (5,-1)
slope=(-1-4)/(5-(-3))=-5/(5+3)=-5/8
slope=-5/8
1/5 divided by 6
6 = 6/1
When dividing fractions, we follow a rule called "Keep, change, flip."
It then becomes: 1/5 * 1/6 = 1/30
1 fifth divided by 6 equals 1/30
The slope of the line that contains the point (13,-2) and (3,-2) is 0
<em><u>Solution:</u></em>
Given that we have to find the slope of the line
The line contains the point (13,-2) and (3,-2)
<em><u>The slope of line is given as:</u></em>

Where, "m" is the slope of line
Here given points are (13,-2) and (3,-2)

<em><u>Substituting the values in formula, we get,</u></em>

Thus the slope of line is 0
(x+1) x (3x-4) is the answer
Step-by-step explanation:
2-×^2
t(×)=3×
(s o t )(x)=st(×)=s(t(x))=2-(3×)^2=2-9x^2
(s o t)(-7) =2-9(-7)^2=2-9(49)= 2-441= -439