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Elena-2011 [213]

1 year ago

7

Find the value of x in the diagram shown below.

1 answer:

Serggg [28]1 year ago

6 0

Answer:

<u>∠DFA = 82°</u>

Step-by-step explanation:

According the property of inscribed angles and arcs, the angle is half of the arc length.

Solving :

∠CFB = 1/2 x ∡CB
∠CFB = 1/2 x 164°
∠CFB = 82°
∠CFB = ∠DFA (Vertically Opposite Angles)
<u>∠DFA = 82°</u>

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zimovet [89]

Answer:

i think im late

Step-by-step explanation:

4 0

2 years ago

12а + 7x - За – 2х what's the answer<br>

Troyanec [42]

9a-5x

step by step explanation:

you can only add and subtract numbers that have the same variables.

12a and 3a are related because there variable is both a.

when u subtract 12a-3a you get the answer of 9a using subtraction.

7x and -2x are the second pair of related terms because they also have the same variable (x)

7x-2x is 5x using subtraction.

put the expression together:

9a-5x

hope this helps!

give me brainliest if it did plz

8 0

2 years ago

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

So

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

So

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

3 years ago

PLEASE HELP MEEEEEE I AM SOOOOOOOOOOOO CONFUZED

Nookie1986 [14]

44 square inches :) you add all of the sides together. You also have to find the sides that weren’t listed.

6 0

3 years ago

Explain how to graph -6y = -2x + 24 using slope and the y intercept. *

bogdanovich [222]

Hello!

Slope intercept form is y = mx + b

m is the slope

b is the y-intercept

To turn the equation into the base form we have to get y by itself

-6y = -2x + 24

Divide both sides by -6

$y=\frac{2}{6} x - 4$

Simplify

$y=\frac{1}{3} x - 4$

To get the y-intercept we put 0 in for the x point and b for the y point

The y-intercept is (0, -4)

The slope is 1/3 which means every time x goes up by 3 the y goes up by 1

Other points are (3, -3) (6, -2) and (9, -1)

With 3 or more points we can plot a graph

Hope this Helps!

4 0

3 years ago