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Andrej [43]
3 years ago
9

5x - 2>13 SOLVE THIS PLEASE STEP BY STEP ASAP

Mathematics
1 answer:
drek231 [11]3 years ago
3 0
5x-2>3
=> 5x > 3+2
=> x > 5/5
=> x > 1
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24x-12-43x-6 <br> Simplify.<br> Please help!! ASAP!!
sergiy2304 [10]

Answer:

-30

Step-by-step explanation:

Hope this helps! Brainliest is appriciated.

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Brainly is a platform that is used to help students in need. There are many social networks that offer socializing with many people from every country in the world.

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The formula for finding the area of a circle is A=pi r 2.Solve the formula for r
olga55 [171]

Answer:

See Explanation

Step-by-step explanation:

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3 0
3 years ago
Solve the system of equations using substitution:<br> 6x – y = –15<br> X + 2y = 17
defon

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x = -1

y = 9

Step-by-step explanation:

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3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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