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GrogVix [38]
2 years ago
14

At the beach, Cody saw 4 times as many

Mathematics
2 answers:
loris [4]2 years ago
8 0
  • Pellicans be y
  • Seagulls be 4y

ATQ

  • y+4y=30
  • 5y=30
  • y=6

Pellicans are 6

Rainbow [258]2 years ago
6 0

Answer:

6 pelicans

Step-by-step explanation:

Let x = number of pelicans

Cody saw 4 times as many seagulls as pelicans:

⇒ number of seagulls = 4x

Total of 30 birds:

⇒ seagulls + pelicans = 30

⇒ 4x + x = 30

⇒ 5x = 30

⇒ x = 6

Therefore, there were 6 pelicans (and 24 seagulls).

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Let f(x)=2x+3 and g(x)=x×x-1<br>find a. f(g(x)) b.g(f(x))<br><br>​
Talja [164]

Answer:

See explanations below

Step-by-step explanation:

Given the functions f(x)=2x+3 and g(x)=x^2-1

a. Find f(g(x))

f(g(x)) = f(x^2-1)

f(g(x)) = 2(x^2-1)+3

f(g(x))= 2x^2-2+3

f(g(x)) = 2x^2+1

Hence the composite function f(g(x)) is 2x^2+1

b) g(f(x)) = g(2x+3)

g(f(x) = (2x+3)^2-1

g(f(x)) = 4x^2+12x+9-1

g(f(x)) = 4x^2+12x+8

5 0
2 years ago
15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c
solniwko [45]

Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

-f(x)=x^2

To prove that  the function is objective from R to  (0,\infty)

Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

(x_1)^2=(x_2)^2

Cancel power on both side then we get

x_1=x_2

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

3 0
3 years ago
Quisssssssss !!!!<br><br>x + 2x + 9y - 7y​
fomenos
<h2>{\orange {\boxed {\colorbox {black} {\orange {King\:Brainly01}}}}}</h2>

\:

◇◆□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□◆◇

x + 2x + 9y - 7y

3x + ( 9y - 7y )

3x + 2y

◇◆□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□◆◇

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4 0
2 years ago
Read 2 more answers
I NEED ANSWER SUPER BAD PLEASE!!!!!!!!!!!What is the greatest integer less than 100 for which the greatest common divisor of tha
PtichkaEL [24]

Answer:

92

Step-by-step explanation:

We will list out the numbers which are factors of 12. They include:

1, 2, 3, 4, 6, 12.

We need to get the highest number that has its greatest factor to be 4. It means that 6 and 12 cannot divide it.

To do this, we will write out the multiples of 4. They include:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88,92,96.

We will have to choose the highest number which only 4  can divide and  6 and 12 cannot divide.

Since we are looking for the largest, We can try dividing all the numbers by 4, 6, and 12 starting from 96.

We will quickly see that 4 can divide 92 but 6 and 12 cannot.

This gives us 92 as the answer.

4 0
2 years ago
Help would be nice‍♀️.
11111nata11111 [884]

Answer:

the ones with a line above the numbers are repeating decimals

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3 years ago
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