Answer:
If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.
the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).
Step-by-step explanation:
Answer:
D. (4,3)
Step-by-step explanation:
(-3,4)
Reflection in the y-axis:
Same y, -ve x
(3,4)
Reflection in y = x
(x,y) goes to (y,x)
(3,4) goes to (4,3)
Answer:
165.
~
Sorry, I can't really show you how I divided it on pc- ¯\_(ツ)_/¯
first one since it’s 1/16 simplest form or 11/17 cuz it’s obv
Answer:
- (2x + 5)/(x - 9)
- 3. quantity 2 x plus 5 over x minus 9
Step-by-step explanation:
Quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36
- (2x² + 13x + 20)/(x² -5x - 36) =
- (2x²+ 5x + 8x + 20)/(x² - 9x + 4x -36)=
- (2x + 5)(x + 4)/(x - 9)(x + 4) =
- (2x + 5)/(x - 9)
Correct option is option 3
