Answer:
Decimal 1/20= .05
Percent 1/20= 5%
Step-by-step explanation:
Step-by-step explanation:
u should:
7t = t + 48 » 7t - t = 48 » 6t = 48 » t = 8
and another one is:
2u + t + 13 = 10t + u - 44» 2u + 8 + 13 = 80 + u - 44»
» 2u + 21 = u + 36 » 2u - u = 36 - 21 » u = 15
What you would do is take the denominators and multiply them by each other, then multiply the numerators by that same number. So like 4/10 and 4/9. You would say, (denominators) 10x9=90 and (numerators) 4x9=36. So your first fraction would be 36/90. Next, you would take (denominators) 9x10=90 and (numerators) 4x10=40. So your second fraction would become 40/90. Now it's a lot easier to compare. 36/90 < 40/90 would be the answer to my problem. I hope I helped!
Answer:
y=-3x-16
Step-by-step explanation:
y-y1=m(x-x1)
y-(-7)=-3(x-(-3))
y+7=-3(x+3)
y=-3x-9-7
y=-3x-16
<h3>Answer:</h3>
- ABDC = 6 in²
- AABD = 8 in²
- AABC = 14 in²
<h3>Explanation:</h3>
A diagram can be helpful.
When triangles have the same altitude, their areas are proportional to their base lengths.
The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...
... BC : EC = (1+5) : 5 = 6 : 5
so ABDC will be 6/5 times AEDC.
... ABDC = (6/5)×(5 in²)
... ABDC = 6 in²
_____
The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...
... AABD : ABDC = AD : DC = 4 : 3
so AABD will be 4/3 times ABDC.
... AABD = (4/3)×(6 in²)
... AABD = 8 in²
_____
Of course, AABC is the sum of the areas of the triangles that make it up:
... AABC = AABD + ABDC = 8 in² + 6 in²
... AABC = 14 in²