4. The sum of the reciprocals of two consecutive even integers is 11/60.Find the integers.

Mathematics

1 answer:

Vikentia [17]1 year ago

8 0

The integers are 10 and 12.

Hope this helps!

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Does anyone how to solve this sum? It’s urgent

Galina-37 [17]

The required value for the sum is 9580.

$\frac{10000}{(1+\frac{0.115}{4})^2}+68\frac{1-\frac{1}{(1+\frac{0.115}{4})^2}}{\frac{0.115}{4}}$

<h3>What is simplification?</h3>

Simplification in mathematics to solve the given condition on its operators.

$\frac{10000}{(1+\frac{0.115}{4})^2}+68\frac{1-\frac{1}{(1+\frac{0.115}{4})^2}}{\frac{0.115}{4}}$

= $\frac{10000}{1.028^2} +68*\frac{1-\frac{1}{1.028^2} }{\frac{0.115}{4} } \\9451+68*\frac{1-0.94}{\frac{0.115}{4} } \\\\9451+68*\frac{0.054}{\frac{0.115}{4} } \\\\\\9451+3.72{\frac{4}{0.115} } \\\\\\9451+129\\$

= 9580

The required solution is given as 9580.

Learn more about simplification here:
brainly.com/question/9218183

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WILL MARK BRAINLIEST IF CORRECT!!!

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I got C. 92.08

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