You can use the following equation:
10h+3p+0.5r=100
This equation uses “h” “p” and “r” to represent the number of animals bought, each variable having a coefficient which is that animal's price. The right side is the total price.
You will now need a second equation so you can proceed to substitution/elimination:
h+p+r=100
This equation, using the same variables, represents the total number of animals to be bought.
We can eliminate the “h” variable by multiplying the bottom equation by -10, you now have the following:
10h+3p+0.5r=100
-10h-10p-10r=-1000
Add down and the result is:
-7p-9.5r=-900
You can set up a proportion
-9.5r=-900+7p
r=(-900+7p)/-9.5
And substitute in the original equation…
P.S. I challenge you to figure out the rest on your own because it is really just a tedious process of substitution and elimination from here and my phone is about to die. I'll check in later if you're still having problems.
Answer:
Most of the men's shoes in the data set cost more than women's shoes.
Step-by-step explanation:
From what I could tell it can't be The price of men's shoes has a higher interquartile range than that of women's shoes. becuse that's false what looks to fit is Most of the men's shoes in the data set cost more than women's shoes. since on the graph more of the mens vaules are bigger
17128.........................
187 ft/s. I think that this might be an equation, but if it is not, I'm sorry.
SA=2hpir+2pir^2=2pir(h+r)
V=hpir^2
SA=339
r=6
339=2pir(h+r)
339=2pi3(h+3)
339=6pi(h+3)
divide both sides by 6pi
56.5/pi=h+3
minus 3 both sides
(56.5/pi)-3=h
(56.5-3pi)/pi=h
v=hpir^2
v=((56.5-3pi)/pi)(pi)(6)^2
v=(56.5-3pi)(36)
v=2034-108pi
use pi=3.141592
v=1694.7079934123023302460345146058
round
1695 cubic cm
