Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
3.5 miles / 1.25 hours = 2.8 mph
Answer:
The answer is option D.
Step-by-step explanation:
(4a - b)(2a - 3b)
Expand the terms
We have
8a² - 12ab - 2ab + 3b²
Which is
8a² - 14ab + 3b²
That's option D.
Hope this helps you
Answers:1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:1) Value of the functions as x increases.Function p:
As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1,
the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.While in the graph you see that the function
q has a horizontal asymptote that shows that the
limit of q (x) when x → ∞ is - 4.Then, the first answer is that
as x increases the value of p(x) approaches a number that is greater than q (x).2) y - intercepts.i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2ii) The y-intercept of q(x) is read in the
graph. It is - 3.
Then the answer is that
the y-intercept of the function p is greater than the y-intercept of the function q.
Walk = x + 6
Bike = x
Driven = x
x + x + x + 6 = 24
combine like terms
3x + 6 = 24
subtract 6 from both sides
3x = 18
divide both sides by 3 to isolate x
x = 6
Walk = x + 6 = 6 + 6 = 12
12 students walk to school.
