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3 years ago

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Can someone help me with this?

1 answer:

mihalych1998 [28]3 years ago

4 0

Can you put a more clear pic up hard to see

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In the expression 12a+5, identify. The coefficient

marysya [2.9K]

A coefficient is a number multiplied by a variable.

In this case, our variable is a.
The coefficient is 12.

(PS: The +5 that isn't being multiplied by a variable is called a constant)

5 0

3 years ago

A grocery store sells a 6-pack of bottle water for $3.79, a 9-pack for $4.50, and a 12-pack for $6.89. Which package costs the l

stiks02 [169]

Cost per bottle

6 pack is 3.79 so the cost per bottle is 3.79/6=$0.631666666666667 per bottle

9 pack is 4.50 so the cost per bottle is 4.50/9=$0.50 per bottle

12 pack is 6.89 so the cost per bottle is 6.89/12=$0.574166666667 per bottle

0.63>0.57>0.50

the one that costs the least per bottle is the 9 pack which costs $0.50 per bottle

5 0

3 years ago

Math homework please help

-BARSIC- [3]

F nbc hbbb b bbb. hey n b

6 0

2 years ago

M=(N-2)/N solve for N

Tpy6a [65]

M = (N-2)/N

M = N² - 2N

N² - 2N - M = 0

To find N we need to use quadratic formula.

For our equation x = N, a=1, b= -2, c= -M

$x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}
\\ \\N=\frac{-(-2)+/-\sqrt{(-2)^{2} -4*1*(-M)} }{2*1}
\\ \\ N=\frac{2+/-\sqrt{4+4M} }{2} \\ \\ N=\frac{-2+/-2\sqrt{1+M} }{2} = -1+/-\sqrt{1+M} \\ \\ N = -1 +\sqrt{1+M} \ or\ N=-1-\sqrt{1+M}$

4 0

3 years ago

David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let <em>A</em><em> </em>= 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, <em>b</em>, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, <em>C</em>, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When <em>b </em>= 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, <em>B'</em>, is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

brainly.com/question/4372174

#SPJ1

4 0

2 years ago