You line the segments up in order from the first quad to the second.
The only one that lines up is AG and NP the first option.
The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
Answer:
you can't combine them
Step-by-step explanation:
Answer:
C po ang Alam kong sagot
Step-by-step explanation:
it's look like a test
Let the width = x
=>length = 2x-1
91= x(2x-1)=2x^2-x
2x^2-x-91=0
=(2x+13)(x-7)
=> x=-13/2=> no
=>x= 7 cm
