First Method:
Round 
to the closest integer, which is 1.
Round 
to the closest integer, which is also 1.
So 1 + 1 = 2.
Answer for method 1: 2
Second Method:
+ = 
is around 1
Answer for method 2: 1
The closest answer is 1.
Answer:
15 nuts do not get found.
Step-by-step explanation:
Given that Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found.
Total number of nuts squirrel had hidden = 40
Proportion of nuts not found to total = 3/(3+5) = 3/8
Hence out of 40, nuts not found =3/8(40) = 15 nuts.
15 nuts would not be found and 25 nuts would be found if squirrel had hidden in total 40 nuts.
This is because the proportion of found:unfound = 5:3
Hence 25:!5 =5:3 satisfies this
15 nuts are not found.
Answer:
D
Step-by-step explanation:
24-6 = 18 32-6x3=18
Hope this helped!
Explanation:
Basically, you can do it in many ways. But just, in my opinion, exactly linear algebra was made for such cases.
the optimal way is to do it with Cramer's rule.
First, find the determinant and then find the determinant x, y, v, u.
Afterward, simply divide the determinant of variables by the usual determinant.
eg. 
and etc.
I think that is the best way to solve it without a hustle of myriad of calculations reducing it to row echelon form and solving with Gaussian elimination.
Answer:
The answer is $1.85
Step-by-step explanation:
<h3>
<u>Given</u>;</h3>
- The cost of 5 chocolate bars = $5.75
- The cost of 2 chocolate bars and 3 packets of sweets = $7.85
<h3>
<u>To </u><u>Find</u>;</h3>
- The cost of one packet of sweets.
Now, we know that the cost of 5 chocolate bars are $5.75.
For 1 chocolate bar
5.75 ÷ 5 = $1.15
Here, we get the price of 1 chocolate bar
So, the cost of 2 chocolate bars and 3 packets of sweets are $7.85.
2 × chocolate bar = 2 × (1.15) = $2.3
Now, we want to find only the cost of one packet of sweets.
So,
7.85 – 2.3 = $5.55
3 packets of sweets cost $5.55
For 1 packets of sweets
5.55 ÷ 3 = $1.85
Thus, The cost of one packet of sweets = $1.85
