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Ivahew [28]
3 years ago
9

2. A two-stage rocket is in development. The required probability is for the overall rocket to be a minimum of 97% reliable for

a successful mission. The first stage is a previously developed design with a known reliability of 99%. The reliability measures for the two stages are independent. What must the minimum reliability for the second stage be
Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer: The minimum reliability for the second stage be 0.979.

Step-by-step explanation:

Since we have given that

Probability for the overall rocket reliable for a successful mission = 97%

Probability for the first stage = 99%

We need to find the minimum reliability for the second stage :

So, it becomes:

P(overall reliability) = P(first stage ) × P(second stage)

0.97=0.99\times x\\\\\dfrac{0.97}{0.99}=x\\\\0.979=x

Hence, the minimum reliability for the second stage be 0.979.

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Step-by-step explanation:

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This grid follows two rules.
fredd [130]

Answer:

a = 4,

b = 12

c = 10

d = 15

Step-by-step explanation:

Since the product of each column is equal, therefore,

b*5 = 60

b = 60 ÷ 5 = 12

c*6 = 60

c = 60 ÷ 6 = 10

Since the sum of each column are equal, therefore,

12 + 10 + a = 5 + 6 + d

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Think of a number you can add to 22, and another number you can add to 11, which will make both sides equal. Add both numbers, whenmultiplied together should give you 60.

Factors of 60 are:

(a, d)

(1, 60) => 22 + a = 11 + d => 22+1 = 11+60 (incorrect)

(2, 30) => 22 + a = 11 + d => 22+2 = 11+30 (incorrect)

(3, 20) => 22 + a = 11 + d => 22+3 = 21+20 (incorrect)

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Therefore,

a = 4,

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