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Ivahew [28]
3 years ago
9

2. A two-stage rocket is in development. The required probability is for the overall rocket to be a minimum of 97% reliable for

a successful mission. The first stage is a previously developed design with a known reliability of 99%. The reliability measures for the two stages are independent. What must the minimum reliability for the second stage be
Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer: The minimum reliability for the second stage be 0.979.

Step-by-step explanation:

Since we have given that

Probability for the overall rocket reliable for a successful mission = 97%

Probability for the first stage = 99%

We need to find the minimum reliability for the second stage :

So, it becomes:

P(overall reliability) = P(first stage ) × P(second stage)

0.97=0.99\times x\\\\\dfrac{0.97}{0.99}=x\\\\0.979=x

Hence, the minimum reliability for the second stage be 0.979.

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Select the correct answer.
Sidana [21]

Answer:c

Step-by-step explanation:

when you set (x-6) and (x-1) to zero you get 6 and 1

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2 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
Nikitich [7]

You are given that all three sides are equal. You also know that all three angles are also equal. Therefore since all three angles are equal and every triangle has 180 degrees, each angle is 180/3 = 60

So

7x - 3 = 60                     Add three to both sides

7x - 3 + 3 = 60 + 3        Combine

7x = 63                          Divide by 7

7x/7 = 63/7

x = 9                              And that's your answer.

3 0
3 years ago
It takes 20 hours and $400 to interview a candidate, and it takes 120 hours and $3600 to train an employee. A company has less t
zavuch27 [327]
<span>Let C denote the number of candidates they interview and E the number of employees they train.
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<span>If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.
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If <span>it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.
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Company has less than <span>$95000, then 400C+3600E<95000.
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Company <span>wants to spend at most 470 hours, then 20C+120E\le&#10; 470.
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<span>You obtain the system of two inequalities:
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\left \{ {{400C+3600E\ \textless \ 95000} \atop {20C+120E\le&#10; 470}} \right.  \\  \left \{ {{4C+36E\ \textless \ 950} \atop {C+6E\le &#10;23.5}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {4C+24E\le &#10;94}} \right.
Then you can solve this system according to your demands.






3 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
2 years ago
Last week, the daily low temperatures for a city, in degrees Celsius, were 5, 8, 6, 5, 10, 7, and 1. What was the average low te
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The average low temperature would be 5+8+6+5+10+7+1 all divided by 7, so the answer is 6° celsius.
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3 years ago
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