All categories

2 years ago

2x to the 2 power minus 14x + 24

Mathematics

1 answer:

Rudik [331]2 years ago

7 0

Answer:

2x^2 +14x +24

Step-by-step explanation:

quadratic expression

You might be interested in

Given function of f(x) = 2x - 1 and fg(x) = 10x + 3, find the function of g(x)

denis-greek [22]

Answer:

The function of g(x) = 5x + 2

Step-by-step explanation:

Let us use the composite function to solve the question

∵ f(x) = 2x - 1

∵ f(g(x)) = 10x + 3

→ f(g(x)) means substitute x in f(x) by g(x)

∴ f(g(x)) = 2[g(x)] - 1

→ Equate the two right sides of f(g(x))

∴ 2[g(x)] - 1 = 10x + 3

→ Add 1 to both sides

∴ 2[g(x)] - 1 + 1 = 10x + 3 + 1

∴ 2[g(x)] = 10x + 4

→ Divide each term into both sides by 2

∵ $\frac{2[g(x)]}{2}$ = $\frac{10x}{2}$ + $\frac{4}{2}$

∴ g(x) = 5x + 2

∴ The function of g(x) = 5x + 2

7 0

3 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

3 years ago

Which of the following equations is used to find the value of c?

erica [24]

Answer:

D. $a^{2} + b^{2} = c^{2}$

Step-by-step explanation:

Pythagorean Theorem

5 0

2 years ago

Read 2 more answers

The 10th term of an a.p is -27 and the 5th term is -12 .find the first term?

horsena [70]

Step-by-step explanation:

$a_{10} = - 27... (Given) \\\\\therefore a + 9d = - 27...... (1)\\\\a_{5} = - 12... (Given) \\\\\therefore a + 4d = - 12.......(2)\\\\$

Subtracting equation (2) from equation (1)

$a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\$

Substituting d = - 3 in equation (1), we find:

$a + 9\times (-3)= - 27\\\\\therefore a - 27 = - 27\\\\\therefore a = 27- 27\\\\\huge \red {\boxed {\therefore a = 0}}\\\\$

Hence, first term is zero.

3 0

3 years ago

When the solution of x2 − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r? x equ

jarptica [38.1K]

Answer:

r = 105

Step-by-step explanation:

Given quadratic equation:

x² − 9x − 6

Quadratic formula is given by:

(-b ± √b² - 4ac) ÷ 2a

For the equation: x² - 9x - 6

a = 1, b = -9 and c = -6

Substitute in the quadratic formula:

(-b ± √b² - 4ac) ÷ 2a

(-(-9) ± √(-9)² - 4(1*-6)) ÷ 2*1

= 9 ± √105 / 2

The solution of x² − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2

Therefore, the value of r is 105

4 0

3 years ago