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1 year ago

I need help

Mathematics

1 answer:

algol [13]1 year ago

5 0

Answer:

1. No.

2. Yes, there is no solution here.

Step-by-step explanation:

The former:

$8(5x - 3) = 6(-3x - 4); \\ 8 * 5x - 8 * 3 = 6 * (-3x) - 6 * 4; \\ 40x - 24 = -18x - 24; \\ 40x + 18x = -24 + 24; \\ 58x = 0; \\ x = 0.$

$\{0\}$ is our set of solutions.

The latter:

$3x - 13 = 7(x + 2) - 4(x - 7); \\ 3x - 13 = 7x + 7 * 2 - 4x - 4 * (-7); \\ 3x - 13 = 7x + 14 - 4x + 28; \\ 7x - 4x - 3x = -13 - 14 - 28;\\ 0x = 55; \\ x \in \emptyset.$

In other words, there is not any solution from the set of real numbers that suits us.

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2 years ago

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<h3>Original Equation:</h3>

$-\frac{1}{3}+2z=-\frac{5}{6}$

<h3>Steps:</h3>

<em>*To solve for a variable, isolate the desired variable onto one side.</em>

Firstly, we want to add 1/3 to each side however -5/6 and 1/3 do not share the same denominator, and we want them to have that and we can do that by finding the LCD, or lowest common denominator. To find the LCD, list the multiples of 6 and 3 and the lowest multiple that they share is their LCD. In this case, their LCD is 6. Multiply -1/3 by 2/2:

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Next, you want to cancel out 2 to isolate z. Usually, one would divide both sides by 2, however remember that <u>dividing by a number is the same as multiplying by it's reciprocal.</u> To find a number's reciprocal, flip the numerator and denominator around. In this case, since 2 is a <em>whole number</em> this means that the denominator is 1. In this case: 2/1 would become 1/2. Multiply both sides by 1/2:

$\frac{1}{2}\times 2z= -\frac{1}{2}\times \frac{1}{2}\\\\z=-\frac{1}{4}$

<h3>Final Answer:</h3>

<u>Your final answer is z = -1/4.</u>

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