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2 years ago

I need help

Mathematics

1 answer:

algol [13]2 years ago

5 0

Answer:

1. No.

2. Yes, there is no solution here.

Step-by-step explanation:

The former:

$8(5x - 3) = 6(-3x - 4); \\ 8 * 5x - 8 * 3 = 6 * (-3x) - 6 * 4; \\ 40x - 24 = -18x - 24; \\ 40x + 18x = -24 + 24; \\ 58x = 0; \\ x = 0.$

$\{0\}$ is our set of solutions.

The latter:

$3x - 13 = 7(x + 2) - 4(x - 7); \\ 3x - 13 = 7x + 7 * 2 - 4x - 4 * (-7); \\ 3x - 13 = 7x + 14 - 4x + 28; \\ 7x - 4x - 3x = -13 - 14 - 28;\\ 0x = 55; \\ x \in \emptyset.$

In other words, there is not any solution from the set of real numbers that suits us.

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Answer:

13.1 (3sf)

Step-by-step explanation:

14 ^2 - 5^2 = 171

root 171 = 13.1 (3sf)

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2 years ago

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PLEASE HELP ASAP!!!

barxatty [35]

Answers:

<u>24000 dollars</u> invested at 4%
<u>18000 dollars</u> was invested at 7%

======================================================

Work Shown:

x = amount invested at 4%

If she invests x dollars at 4%, then the rest (42000-x) must be invested at the other rate of 7%

She earns 0.04x dollars from that first account and 0.07(42000-x) dollars from the second account

This means we have

0.04x+0.07(42000-x)

0.04x+0.07*42000-0.07x

0.04x+2940-0.07x

-0.03x+2940

This represents the total amount of money earned after 1 year.

We're told the amount earned in interest is $2220, so we can say,

-0.03x+2940 = 2220

-0.03x = 2220-2940

-0.03x = -720

x = -720/(-0.03)

x = 24000 dollars is the amount invested at 4%

42000-x = 42000-24000 = 18000 dollars was invested at 7%

----------------------

As a check, we can see that

18000+24000 = 42000

and also

0.04x = 0.04*24000 = 960 earned from the first account

0.07*18000 = 1260 earned from the second account

1260+960 = 2220 is the total interest earned from both accounts combined

This confirms our answers.

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3 years ago

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Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

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3 years ago

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My name is Ann [436]

Answer:

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