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3 years ago

14

the ratio of the circumfrence of two circles is 3/2 the radius of the smaller circle is 8 inches what is the radius of the large

r circle

1 answer:

Arisa [49]3 years ago

6 0

The answer is 12 inches! let me know if you need an explanation.

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What is the value of x in the equation 4 and StartFraction 3 Over 10 EndFraction minus (2 and two-fifths x + 5 and one-half) = o

musickatia [10]

Answer:

5

Step-by-step explanation:

Edge i think dont quote me on this plz

3 0

3 years ago

Which quadratic equation has solutions x=8 and x=−1?

andrezito [222]

There are two ways you can do this

$Using the formula$

${x}^{2} - (sum \: of \: roots)x + poduct \: of \: roots = 0$

${x}^{2} - (8+-1)x + - 1 \times 8 = 0$

${x}^{2} - 7x - 8 = 0$

$Working backwards$

$x = 8 \: or \: x = - 1$
$\Rightarrow x-8=0 \: or \: x+1=0$

$\Rightarrow (x-8)(x + 1)=0$
$\Rightarrow {x}^{2} + x -8x - 8 = 0$
$\Rightarrow {x}^{2} - 7x - 8 = 0$

7 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

2 years ago

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Yola paid $20 for 8.7 gallons of gas. victor paid $30 for 12.4 gallons. compare the price per gallon to fined who got the better

Oksana_A [137]

20$ divided by 8.7 gallons=$2.30

30$ divided by 12.4 gallons=$2.41
Yola got the better deal

8 0

2 years ago

Multiply and place the decimal point in the product of each problem -0.7 x 0.2

Elina [12.6K]

Your answer would be -0.14

8 0

2 years ago

Read 2 more answers