the ratio of the circumfrence of two circles is 3/2 the radius of the smaller circle is 8 inches what is the radius of the large
1 answer:
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Answer:
The answer is and
Step-by-step explanation:
Given:
-4x-2y=14
-10x+7y=-24
Now, to solve it by elimination:
......(1)
......(2)
So, we multiply the equation (1) by 7 we get:
And, we multiply the equation (2) by 2 we get:
Now, adding both the new equations:
<em>Dividing both the sides by -8 we get:</em>
Now, putting the value of in equation (1):
<em>Subtracting both sides by 25 we get:</em>
<em>Dividing both sides by -2 we get:</em>
Therefore, the answer is and
The resultant graph is shown in the attached image.
Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5
Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line.
To know the region, you will simply use trial and error method for random points on the two sides of the line.
The final solution would be as shown in that attachment.
Hope this helps :)
Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5
Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line.
To know the region, you will simply use trial and error method for random points on the two sides of the line.
The final solution would be as shown in that attachment.
Hope this helps :)
Answer:
Step-by-step explanation:
Isolate the term of x from one side of the equation.
<h3>x-5≤10</h3><u>First, add by 5 from both sides.</u>
<u>Solve.</u>
<u>Add the numbers from left to right.</u>
- <u>Therefore, the solution is x≤15, which is our answer.</u>
I hope this helps you! Let me know if my answer is wrong or not.