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Over [174]
2 years ago
12

A rectangle has a width that measures 11 in. and a length that measures 5.5 in.

Mathematics
2 answers:
Katen [24]2 years ago
6 0

Answer: 60.5 in

Step-by-step explanation:

Area of rectangle = length times width

Length = 5.5 in

Width = 11 in

11 x 5.5 = 60.5

The area of the rectangle is 60.5 in

mote1985 [20]2 years ago
4 0
The formula to find the area of a rectangle is A = wl.

A = (11)(5.5)
A = 60.5

The area of the rectangle is 60.5 inches squared.
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Please help and thank you
RideAnS [48]

Answer:

50

Or D (if D is 50)

Step-by-step explanation:

4.5x+396=621

Subtract 396 from both sides. (Subtraction Property of Equality)

4.5x=225

Divide both sides by 4.5 to get x by itself. (Division Property of Equality)

x=50

7 0
3 years ago
the length of a rectangle is 12 inches more than it's width what is it's width of the rectangle if the perimeter is 42 inches​
dimaraw [331]

Answer:

3.5

Step-by-step explanation:

6 0
3 years ago
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Ignore the 30% but I need help!
Brilliant_brown [7]

x² + 9x + 1

let's start by grouping the ones with the same variable

(x² + 9x) + 1

(x² + 9x + [?]²) + 1

so, we seem to be missing a value there, to get a perfect square trinomial, let's recall a perfect square trinomial has a middle term that is 2 * "other two values", namely

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so, the middle term on this group will be 9x.

we know 2*x*[?] = 9x, so then

\bf 2\cdot x\cdot \boxed{?}=9x\implies \boxed{?}=\cfrac{9x}{2x}\implies \boxed{?}=\cfrac{9}{2}


so that's our mystery felllow.

now, let's bear in mind that we'll be borrowing from our very good friend Mr Zero, 0, so if we add (9/2)², we also have to subtract (9/2)².


\bf \left[x^2+9x+\left( \cfrac{9}{2} \right)^2 - \left( \cfrac{9}{2} \right)^2 \right]+1\implies \left[x^2+9x+\left( \cfrac{9}{2} \right)^2 \right]+1- \left( \cfrac{9}{2} \right)^2 \\\\\\ \left( x+\cfrac{9}{2} \right)^2+1-\cfrac{81}{4}\implies \left( x+\cfrac{9}{2} \right)^2-\cfrac{77}{4}

7 0
4 years ago
Solve for theta in the interval 0&lt;theta&lt;2pi.     <br>cos(theta)sin(theta)-0.5 cos(theta)=0
riadik2000 [5.3K]
CosOsinO - 0.5 cosO = 0

cosO(sinO - 0.5) = 0

so cosO = 0 ,  sin O = 0.5

cosO = 0  gives O = pi/2 , 3pi/2
sinO = 0.5  gives O = pi/6, 5pi/6.
4 0
3 years ago
Read 2 more answers
Find the area. yes it is a right triangle and I'm a somewhat sure angle in the bottom left is 60°
Taya2010 [7]

Answer:ill help all triangles should equal to 180 hope it did help you

Step-by-step explanation:

4 0
4 years ago
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