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2 years ago

I will give brainliest if anyone answers this : Would you like to be my friend on brainly? :)

Mathematics

2 answers:

Artyom0805 [142]2 years ago

7 0

Answer:

alr then bet

Step-by-step explanation:

Misha Larkins [42]2 years ago

6 0

Answer:

Yes

Step-by-step explanation:

I would love to be your friend

PEOPLE WHO REPORT THESE QUESTIONS YOU NEED HELP LEAVE THE GUY ALONE!!!! SIME OF US JUST NEED FRIENDS

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What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)

BigorU [14]

If the term in the middle is 16x^2

6x^2-24x-16x^2-9x+1 =

-10x^2-33x+1

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2 years ago

3. What is the slope of the table shown? Cars Washed Number Money ($) 5 40 10 80 15 120 20 160

IceJOKER [234]

The slope is 8.
(5,40) (10,80)
80-40=40
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2 years ago

How do I factorise an expression

ololo11 [35]

It factorises to -
4(x+6)

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2 years ago

NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.

slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

$\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2$

<u>Total Surface Area</u>

Area of the isosceles triangle:

$\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2$

Total surface area:

$\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)$

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

$\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2$

<u>Total Surface Area</u>

Area of a pentagon:

$\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2$

where a is the side length.

Therefore:

$\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)$

Total surface area:

$\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)$

8 0

1 year ago

A trapezoid has an area of 294 square yards. Its height is 14 yards and the length of one base is 30 yards. Find the length of t

nordsb [41]

Your answer is 250 yards you basically just subtract the numbers it gives you from the 294....

5 0

3 years ago