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2 years ago

How to evaluate this question

Mathematics

2 answers:

sergey [27]2 years ago

6 0

Answer:

${2x}^{3} - 3yz$

x=-1; y=-2 and z=3

$2 {( - 1)}^{3} - 3( - 2)(3)$

$- 2 +6(3)$

$- 2 +18$

(-)+(+)=(-)

$-16$

Harlamova29_29 [7]2 years ago

3 0

The answer is 16

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Drop comments if any doubt arises.

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Tyler's bag of shells weighs 4.97 pounds. He finds 2 stones that weigh the same as each other and adds them to the bag. Tyler's

LUCKY_DIMON [66]

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it should be 0.7

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3 years ago

Formulas A=bh/2 A=bh and I have 6in 4in 6in 10in and I have to find the area

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Answer:

Lots of "ifs" here.

A=bh/2 is the formula for the area of a triangle.

A=bh is the formula for the area of a rectangle or a parallelogram.

If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2

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3 years ago

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4 years ago

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Colt1911 [192]

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3 years ago

There are 10 sweets in a bag.

Valentin [98]

Answer:

See Explanation Below

Step-by-step explanation:

Given

Total Sweets = 10

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Green = 2

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Purple = 1

Required

a & b

The question is not properly presented; however the solution is as follows;

Let P(Yellow) represent the probability of selecting a yellow sweet and n(Yellow) represent the number of Yellow sweets;

$P(Yellow) = \frac{n(Yellow)}{Total}$

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So, whichever letter that shows $0.4$ or $\frac{4}{10}$ is the probability of choosing a yellow sweet

Let P(Orange) represent the probability of selecting an orange sweet and n(Orange) represent the number of orange sweets;

Since, there's no orange sweet in the bag;

$n(Orange) = 0$

$P(Orange) = \frac{n(Orange)}{Total}$

$P(Orange) = \frac{0}{10}$

$P(Orange) = 0$

In probability; opposite probabilities add up to 1;

Let P(Not\ Orange) represent the probability of choosing a sweet that is not orange

$P(Not\ Orange) + P(Orange) = 1$

Substitute $P(Orange) = 0$

$P(Not\ Orange) + 0 = 1$

$P(Not\ Orange) = 1$

So, whichever letter that shows 0 is the probability of choosing a sweet that is not orange

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3 years ago