Match each number with its place in order from smallest (1st) to largest (6th).

Evaluate 18 divided 2a if a = 3

Andreas93 [3]

Answer:

3

Step-by-step explanation:

$\frac{18}{2a}$

a = 3

$\frac{18}{2(3)}$

multiply 2 and 3

2 * 3 = 6

$\frac{18}{6}$

simplify

18/6 = 3

5 0

3 years ago

Which of the following represents the quotient of the polynomial 6x^3+3x^2-5/3x^2+1

fenix001 [56]

Answer: The quotient is (2x+1)

Step-by-step explanation:

Here, the dividend = $6x^3+3x^2-5$

Divisor = $(3x^2+1)$

By the long division method for finding the quotient we will follow the following steps,

Steps 1 : Write dividend inside the division sign and divisor outside the division sign,

Step 2: Multiply the divisor by 2x and subtract the result by the dividend,

Step 3: Now, again multiply the divisor by 1,

Step 4: Subtract the result by the remaining dividend,

Since, further division is not possible,

Hence, the sum of all terms that are multiplied = 2x+1

Which is our quotient.

4 0

3 years ago

(03.05 MC) Solve the rational equation x divided by 2 equals x squared divided by quantity x minus 2 end quantity, and check for

ycow [4]

Answer:

x = 0 and x = -2 are solutions of the given rational equation.

Step-by-step explanation:

We must solve the following rational equation:

$\frac{x}{2} = \frac{x^{2}}{x-2}$

Now we present the procedure:

1) $\frac{x}{2} = \frac{x^{2}}{x-2}$ Given

2) $x\cdot (x-2) = 2\cdot x^{2}$ Compatibility with multiplication/Existence of the multiplicative inverse/Definition of division/Modulative property.

3) $x^{2}-2\cdot x = 2\cdot x^{2}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

4) $x^{2} + 2\cdot x = 0$ Compatibility with addition/Existence of the additive inverse/Modulative property/Reflexive property

5) $x \cdot (x+2) = 0$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

6) $x = 0\, \lor\, x = -2$ Result

Now we check the rational equation with each root:

x = 0

$\frac{x}{2} = \frac{x^{2}}{x-2}$

$\frac{0}{2} = \frac{0^{2}}{0-2}$

$0 = \frac{0}{-2}$

$0 = 0$

x = 0 is a solution of the rational equation.

x = -2

$\frac{x}{2} = \frac{x^{2}}{x-2}$

$\frac{-2}{2} = \frac{(-2)^{2}}{-2-2}$

$-1 = -1$

x = -2 is a solution of the rational equation.

4 0

3 years ago

Is it A) , B) , C), D) , E)

Mrac [35]

Answer:

Part A) The statement is True

Part B) The statement is False

Part C) The statement is True

Part D) The statement is True

part E) The statement is False

Step-by-step explanation:

Part A) we have

$1.66..=1 \frac{6}{9}$

The statement Is True

Convert the repeating decimal 1.66.. to an equivalent fraction

Let

$x=1.66..\\ 10x=16.66..\\ 10x-x=16.66..-1.66..\\ 9x=15\\ x=15/9$

Convert to mixed number

$15/9=9/9+6/9=1 \frac{6}{9}$

therefore

$1.66..=1 \frac{6}{9}$

Part B) we have

$0.6 < 6\%$

The statement is false

Because

$6\%=6/100=0.06$

so

substitute

$0.6 < 0.06$ -----> is not true

Part C) we have

$45\% \leq4.5$

The statement is True

Because

$45\%=45/100=0.45$

substitute

$0.45 \leq4.5$ ----> is true

Part D) we have

$5^{2} \geq 16$

The statement is True

Because

$5^{2}=25$

substitute

$25 \geq 16$ ----> is true

Part E) we have

$9.25 > 9\frac{3}{4}$

The statement is false

Because

Convert mixed number to an improper fraction

$9\frac{3}{4}=\frac{9*4+3}{4}=\frac{39}{4}$

Convert decimal number to an improper fraction

$9.25=9\frac{1}{4}=\frac{9*4+1}{4}=\frac{37}{4}$

substitute

$\frac{37}{4} > \frac{39}{4}$ -----> is not true

8 0

3 years ago

Jermaine buys T-shirts for $6 each and marks up the price by 45%. How much more does Jermaine charge for each T-shirt sold?

Tamiku [17]

Answer:

$2.7

Step-by-step explanation:

We find the amount that was marked up

Jermaine buys T-shirts for $6 each and marks up the price by 45%.

The marked up amount = 45% × $6

= 45/100 × $6

= $2.7

Therefore, the amount Jermaine charges more for each T-shirt sold is $2.7

3 0

2 years ago