Answer:
x=53/9
Step-by-step explanation:
(x-2):5=7:9
9x-18=35
9x=35+18
9x=53
x=53/9
Answer:im pretty sure its 64.8
Step-by-step explanation:
Answer: Our required probability is 0.39.
Step-by-step explanation:
Since we have given that
X be the exponentially distributed with mean life = 6 years
So, E[x]=6
![\dfrac{1}{\lambda}=6\\\\\lambda=\dfrac{1}{6}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B%5Clambda%7D%3D6%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7B1%7D%7B6%7D)
So, our cumulative distribution function would be
![F(x)=1-e^{-\lambda x}](https://tex.z-dn.net/?f=F%28x%29%3D1-e%5E%7B-%5Clambda%20x%7D)
We need to find the probability that the CPU fails within 3 years.
![P(X](https://tex.z-dn.net/?f=P%28X%3C3%29%3DF%283%29%3D1-e%5E%7B-%5Cfrac%7B1%7D%7B6%7D%5Ctimes%203%7D%5C%5C%5C%5C%3D1-e%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5Capprox%200.39)
Hence, our required probability is 0.39.
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1