<h2>
Answer:<em>
</em><em><u>
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
</u></em></h2><h2><em><u>
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>
Step-by-step explanation: The prime factorization of 4320 is
2•2•2•2•2•3•3•3•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 4320 = √ 2•2•2•2•2•3•3•3•5 =2•2•3•√ 30 =
± 12 • √ 30
√ 30 , rounded to 4 decimal digits, is 5.4772
So now we are looking at:
w = ( -40 ± 12 • 5.477 ) / -34
Two real solutions:
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757
or:
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
MY HEAD HURTS!
Answer:
D. All those resources can be found in Africa
Answer:
C
Step-by-step explanation:
3x^2 * -x =-3x^3
3x^2 * 2. =6x^2
4x* -x =-4x^2
4x * 2 = 8x
-5 * -x = 5x
-5 * 2 = -10
6x^2 + -4x^2 = 2x^2
8x+5x = 13 x
Ans: -3x^3 + 2x^2 + 13x -10
Answer:
Step-by-step explanation:
number of cards = 52
number of queen = 4
number of spades = 13
A) probability that the tenth card is a queen
drawn time (r) = 1
position of success(x) = 10th
p = 4/52
P( x,r,p) = 
p(10,1,4/52) = 9C0(4/52)^1 * (48/52)^9 = 0.0374
B) probability the twentieth card is a spade
x = 20
r = 1
p = 13 / 52
P(20,1,26/52) = 19C0(26/52)^1 * (26/52)^19 = 0.0010
c) The last five cards been spades
p(last five cards been spades )
p(48..52, 5, 13/52 ) = 47...52C4(13/52)^5 * (39/52)^48..52 - 5
Answer:
1/11 of a gallon
Step-by-step explanation:
He used 2/11 of 1/2 gallon
2/11 * 1/2 = 1/11 of a gallon
