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kolezko [41]
2 years ago
7

Help me please im in a rush i need help

Mathematics
1 answer:
GREYUIT [131]2 years ago
8 0

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

Area of shaded region = 34 cm²

\textsf{  \underline{\underline{Steps to solve the problem} }:}

Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.

Area (big) :

\qquad❖ \:  \sf \:13 \times 6

\qquad❖ \:  \sf \:78 \:  \:c m {}^{2}

Area (small) :

\qquad❖ \:  \sf \:11 \times 4

\qquad❖ \:  \sf \:44 \:  \: cm {}^{2}

Area of shaded region :

\qquad❖ \:  \sf \:78 - 44

\qquad❖ \:  \sf \:34 \:  \: cm {}^{2}

\qquad \large \sf {Conclusion}  :

Area of shaded region = 34 cm²

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A warehouse employs 22 workers on first shift and 14 workers on second shift. Eight workers are chosen at random to be interview
lara [203]
36 all together.
22 first
14 second
8 random chosen

A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29

Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)

B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29

Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)

C) 22/36
21/35
20/34
19/33
18/32
17/31

Multiply..
Probability.. 0.038306451612903


D) 14/36
13/35
12/34
11/33

X... p=0.016993464052288


Probably not correct, haven't done probability in years.
8 0
3 years ago
A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage
fiasKO [112]

We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

\begin{gathered} N=4+10+17+6+2 \\ N=39 \end{gathered}

We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}

This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

For grade B:

RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}

For grade C:

RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}

For grade D:

RF_D=\frac{6}{39}\approx0.1538\approx15.38\text{ \%}

For grade F:

RF_D=\frac{2}{39}\approx0.0513\approx5.13\text{ \%}

4 0
1 year ago
Write each ratio in simplest form.<br> 1. 33/36
Anarel [89]
33 ÷ 3
----------- = 11 / 12.
36 ÷ 3

It's simplest form is 11 / 12.
7 0
3 years ago
IN A CLASS OF 30 STUDENTS 13 OF THEM ARE BOYS WHAT PERCENTAGE ARE GIRLS?
mestny [16]
Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

17/100 in a % form = 17%

The percentage of girls in the class is 17%

5 0
3 years ago
Which will have a higher effective interest rate — a payday loan for $1900 that is due in 14 days with a fee of $80, or a payday
Pie

Answer:

It's D.

Step-by-step explanation:

The shorter period loan has the same total interest for the same loan amount, so it has the higher effective interest rate: 80/12 is higher than 89/14.

6 0
3 years ago
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