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kolezko [41]
2 years ago
7

Help me please im in a rush i need help

Mathematics
1 answer:
GREYUIT [131]2 years ago
8 0

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

Area of shaded region = 34 cm²

\textsf{  \underline{\underline{Steps to solve the problem} }:}

Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.

Area (big) :

\qquad❖ \:  \sf \:13 \times 6

\qquad❖ \:  \sf \:78 \:  \:c m {}^{2}

Area (small) :

\qquad❖ \:  \sf \:11 \times 4

\qquad❖ \:  \sf \:44 \:  \: cm {}^{2}

Area of shaded region :

\qquad❖ \:  \sf \:78 - 44

\qquad❖ \:  \sf \:34 \:  \: cm {}^{2}

\qquad \large \sf {Conclusion}  :

Area of shaded region = 34 cm²

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he blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.3 and a standard deviation of 6
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The approximate percentage of women with platelet counts within 3 standard deviations of the​ mean is 99.7%.

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We are given that the blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.3 and a standard deviation of 60.7.

Let X = <em>t</em><u><em>he blood platelet counts of a group of women</em></u>

The z-score probability distribution for the normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 247.3

           \sigma = standard deviation = 60.7

Now, according to the empirical rule;

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Since it is stated that we have to calculate the approximate percentage of women with platelet counts within 3 standard deviations of the​ mean, or between 65.2 and 429.4, i.e;

         z-score for 65.2 =  \frac{X-\mu}{\sigma}

                                     =  \frac{65.2-247.3}{60.7}  = -3

         z-score for 429.4 =  \frac{X-\mu}{\sigma}

                                       =  \frac{429.4-247.3}{60.7}  = 3

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3 years ago
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The question basically want us to check if it follows the ratio.

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80 : 28 which is equivalent to 20 : 7

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