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labwork [276]
1 year ago
5

A farmer has a piece of land with an area of 4 square yards. If a cow can graze grass at a rate of 2 square feet per hour, how l

ong will it take 3 cows to graze the entire piece of land
Mathematics
1 answer:
Lunna [17]1 year ago
8 0

Answer:

2 hours

Step-by-step explanation:

4 square yards to feet: 4*3 = 12ft

3 cows grazing grass at 2 ft per hour: 2*2 = 6 square ft per hour

Time taken: 12ft/6ft per hour = 2 hours

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Simplify the expression help, please<br> 275j+2.25-1.5j+3
Sunny_sXe [5.5K]

Answer:

273.5j+5.25

Step-by-step explanation:

first combine like terms 275j-1.5j. and then 2.25+3

3 0
3 years ago
Read 2 more answers
Can someone help me pls thanks
patriot [66]

If 4600 corresponds with 100, multiply 4600 by .09 and you get 414.

Also:

46 * 9 = 414

5 0
3 years ago
Please help me due today
Keith_Richards [23]

Answer:

To find the answer consider that this is a right triangle and we can use the tangent function in order to find the value of x

remember the acronym soh cah toa.

to use the tangent function we divide the opposite and adjacent side that is what the oa stands for in toa

setting it up looks like this

tan 72° = \frac{x}{8\\}

solving for x gives us x= 8×tan 72°

which is about 24.62

Step-by-step explanation:

4 0
2 years ago
A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen
Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}

The restriction is that the perimeter have to be 12 ft at most:

P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12

We can express b in function of a as:

2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a

Then, the area become:

A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2

To maximize the area, we derive and equal to zero:

\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36

Then, b is:

b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68

3 0
3 years ago
7^(x+4)=-34 solve for x
damaskus [11]

for
x^m=y
that means
log_x(y)=m
so

7^{x+4}=-34 means

log_7(-34)=x+4
minus 4 from both sides
log_7(-34)-4=x

6 0
3 years ago
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