What is the solution to this equation?

-Dominant- [34]

Answer:

The value of m is 3 because (5^4)^3 = 244140625 and 5^12 = 244140625 also, this means they are both equal to each other. Another way of getting the correct answer is just seeing what times 4 will get you 12, as you can see

3 x 4 = 12.

So yea the answer is M = 3.

Step-by-step explanation:

5 0

3 years ago

Emma measured a restaurant and made a scale drawing. The scale of the drawing was 2 centimeters : 1 meter. If the actual width o

soldi70 [24.7K]

Answer:

20000 meters

Step-by-step explanation:

3 0

2 years ago

The amount of carbon-14 in animal bones after t years is given by P(t)=P[0]e^(-0.00012097t). A bone has lost 37% of its carbon-1

Vesna [10]

63 years :) Hope this helps ;D

8 0

3 years ago

What is the new location of the point (7,-8)<br> when it has been rotated 90 degrees?

grandymaker [24]

Answer: The answer is A

Step-by-step explanation:

4 0

2 years ago

Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0

3 years ago